R.K. Singh Solutions for Chapter: SSC Advanced Maths. : Previous Years Solved Papers, Exercise 12: SSC G.L. P.T. Exam.: 21.04.2013

What is the value of $\cos 1°\cos 2°\cos 3°...\cos 177°\cos 178°\cos 179°?$

If $\mathrm{p}-2\mathrm{q}=4$, then find ${\mathrm{p}}^3-8{\mathrm{q}}^3-24\mathrm{pq}-64$

In a right-angled $∆\mathrm{ABC}, \angle \mathrm{ABC}=90°, \mathrm{AB}=5 \mathrm{cm}$ and $\mathrm{BC}=12 \mathrm{cm}.$ Then circumradius of $∆\mathrm{ABC}$ is:

Two circles intersect at $\mathrm{A}$ and $\mathrm{B}$ is a point on the produced part of $\mathrm{BA}. \mathrm{PT}$ and $\mathrm{PQ}$ are tangents. Their relation between $\mathrm{PT}$ and $\mathrm{PQ}$ is:

At a certain time, the length of the shadow of a pole is $\sqrt{3}$ time of its height. The angle of elevation of sun at that time is:

$3(\sin \theta -\cos \theta {)}^4+6(\sin \theta +\cos \theta {)}^2+4\left({\sin }^6\theta +{\cos }^6\theta \right)$ is equal to:

The equation of type $ax+by+c=0,$ where $\mathrm{a}\ne 0, \mathrm{b}\ne 0, \mathrm{c}=0$ represents the equation of a straight line that passes through points.

If ${\mathrm{x}}^2=\mathrm{y}+\mathrm{z}, {\mathrm{y}}^2=\mathrm{z}+\mathrm{x}$ and ${\mathrm{z}}^2=\mathrm{x}+\mathrm{y},$ then the value of $\frac{1}{1+\mathrm{x}}+\frac{1}{1+\mathrm{y}}+\frac{1}{1+\mathrm{z}}$ is: