Ramendra C Mukerjee Solutions for Chapter: Miscellaneous Objective Questions, Exercise 1: Exercise 1

Author:Ramendra C Mukerjee

Ramendra C Mukerjee Chemistry Solutions for Exercise - Ramendra C Mukerjee Solutions for Chapter: Miscellaneous Objective Questions, Exercise 1: Exercise 1

Attempt the practice questions on Chapter 22: Miscellaneous Objective Questions, Exercise 1: Exercise 1 with hints and solutions to strengthen your understanding. Modern Approach to Chemical Calculations solutions are prepared by Experienced Embibe Experts.

Questions from Ramendra C Mukerjee Solutions for Chapter: Miscellaneous Objective Questions, Exercise 1: Exercise 1 with Hints & Solutions

HARD
JEE Main
IMPORTANT

In an electrolysis process, 10 electrons could deposit x kg of a univalent metal M. The atomic weight of M is (N is Avogadro constant.)

EASY
JEE Main
IMPORTANT

Which of the following compound cannot be oxidised by O3?

HARD
JEE Main
IMPORTANT

In which of the following compounds the cations are present in alternate tetrahedral voids

MEDIUM
JEE Main
IMPORTANT

The elevation in boiling point of a solution of 13.44 g of CuCl2 in 1 kg of water using the following information, will be (Molecular weight of CuCl2=134.4 and Kb=0.52 K molal-1) : (Report the answer in two decimal places)

MEDIUM
JEE Main
IMPORTANT

Which of the following choices match(es) with hydrogen gas at 200 atm and 273 K?

HARD
JEE Main
IMPORTANT

A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9

Given,

Kf water=1.86 K kg mol-1Kf ethanol=2.0 K kg mol-1Kb water=0.52 K kg mol-1Kb ethanol=1.2 K kg mol-1

Standard freezing point of water =273 K

Standard freezing point of ethanol =155.7 K

Standard boiling point of water =373 K

Standard boiling point of ethanol =351.5 K

Vapour pressure of pure water =32.8 mmHg 

Vapour pressure of pure ethanol =40 mmHg 

Molecular weight of water =18 g mol-1

Molecular weight of ethanol =46 g mol-1

The vapour pressure of the solution M is

HARD
JEE Main
IMPORTANT

A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9 . Given

Kf(Water)=1.86 K kg mol-1Kf(Ethanol)=2.0 K kg mol-1Kb(Water)=0.52 K kg mol-1Kb(Ethanol)=1.2 K kg mol-1

Standard freezing point of water =273K

Standard freezing point of ethanol =155.7 K

Standard boiling point of water =373 K

Standard boiling point of ethanol =351.5 K

Vapour pressure of pure water =32.8 mmHg 

Vapour pressure of pure ethanol =40 mmHg 

Molecular weight of water =18 g mol-1

Molecular weight of ethanol=46 g mol-1 

Water is added to the solution M such that the mole fraction of water in solution becomes 0.9. What is the boiling point of this solution?

[Hint: Solute is ethanol and solvent is water]

HARD
JEE Main
IMPORTANT

The solubility product Ksp of salts of types MX, MX2 and M3X at a temperature T'' are 4.0×10-8,3.2×10-14 and 2.7×10-15 respectively. Solubilities mol dm-3 of salts at temperature 'T' are in the order: