The tables show the length of time some men and women spent on their mobile phones one day. Time spent in minutes (men) Frequency 0 ≤ x < 15 5 15 ≤ x < 30 8 30 ≤ x < 45 10 45 ≤ x < 60 5 60 ≤ x < 75 2 Time spent in minutes (women) Frequency 0 ≤ x < 15 4 15 ≤ x < 30 5 30 ≤ x < 45 7 45 ≤ x < 60 14 60 ≤ x < 75 20 Calculate the relative frequencies for each class interval.

Given data shows the length of time some men and women spent on their mobile phones one day. Relative frequency of class interval = frequency of class interval Total frequency Now the relative frequency table for men whose total frequency is = 5 + 8 + 10 + 5 + 2 = 30 is given by Time spent in minutes (men) Frequency f Relative frequency 0 ≤ x < 15 5 5 30 = 0 . 16 15 ≤ x < 30 8 8 30 = 0 . 26 30 ≤ x < 45 10 10 30 = 0 . 33 45 ≤ x < 60 5 5 30 = 0 . 16 60 ≤ x < 75 2 2 30 = 0 . 06 Now the relative frequency table for women whose total frequency is = 4 + 5 + 7 + 14 + 20 = 50 is given by Time spent in minutes (women) Frequency f Relative frequency 0 ≤ x < 15 4 4 50 = 0 . 08 15 ≤ x < 30 5 5 50 = 0 . 1 30 ≤ x < 45 7 7 50 = 0 . 14 45 ≤ x < 60 14 14 50 = 0 . 28 60 ≤ x < 75 20 20 50 = 0 . 4

The tables show the length of time some men and women spent on their mobile phones one day. Time spent in minutes (men) Frequency 0 ≤ x < 15 5 15 ≤ x < 30 8 30 ≤ x < 45 10 45 ≤ x < 60 5 60 ≤ x < 75 2 Time spent in minutes (women) Frequency 0 ≤ x < 15 4 15 ≤ x < 30 5 30 ≤ x < 45 7 45 ≤ x < 60 14 60 ≤ x < 75 20 Draw relative frequency histograms for the two sets of data.

Given data shows the length of time some men and women spent on their mobile phones one day. For a data set with n members or total frequency n , a class interval with frequency f has relative frequency f n . Now the relative frequency table for men whose total frequency is = 5 + 8 + 10 + 5 + 2 = 30 is given by Time spent in minutes (men) Frequency f Relative frequency 0 ≤ x < 15 5 5 30 = 0 . 16 15 ≤ x < 30 8 8 30 = 0 . 26 30 ≤ x < 45 10 10 30 = 0 . 33 45 ≤ x < 60 5 5 30 = 0 . 16 60 ≤ x < 75 2 2 30 = 0 . 06 Now the relative frequency table for women whose total frequency is = 4 + 5 + 7 + 14 + 20 = 50 is given by Time spent in minutes (women) Frequency f Relative frequency 0 ≤ x < 15 4 4 50 = 0 . 08 15 ≤ x < 30 5 5 50 = 0 . 1 30 ≤ x < 45 7 7 50 = 0 . 14 45 ≤ x < 60 14 14 50 = 0 . 28 60 ≤ x < 75 20 20 50 = 0 . 4 Now plot the time spent on x - axis and relative frequency on y - axis to construct the Relative frequency histogram of data of men. Now plot the time spent on x - axis and relative frequency on y - axis to construct the Relative frequency histogram of data of women.

The tables show the length of time some men and women spent on their mobile phones one day. Time spent in minutes (men) Frequency 0 ≤ x < 15 5 15 ≤ x < 30 8 30 ≤ x < 45 10 45 ≤ x < 60 5 60 ≤ x < 75 2 Time spent in minutes (women) Frequency 0 ≤ x < 15 4 15 ≤ x < 30 5 30 ≤ x < 45 7 45 ≤ x < 60 14 60 ≤ x < 75 20 Describe each distribution.

Given data shows the length of time some men and women spent on their mobile phones one day. For a data set with n members or total frequency n , a class interval with frequency f has relative frequency f n . Now the relative frequency table for men whose total frequency is = 5 + 8 + 10 + 5 + 2 = 30 is given by Time spent in minutes (men) Frequency f Relative frequency 0 ≤ x < 15 5 5 30 = 0 . 16 15 ≤ x < 30 8 8 30 = 0 . 26 30 ≤ x < 45 10 10 30 = 0 . 33 45 ≤ x < 60 5 5 30 = 0 . 16 60 ≤ x < 75 2 2 30 = 0 . 06 Now the relative frequency table for women whose total frequency is = 4 + 5 + 7 + 14 + 20 = 50 is given by Time spent in minutes (women) Frequency f Relative frequency 0 ≤ x < 15 4 4 50 = 0 . 08 15 ≤ x < 30 5 5 50 = 0 . 1 30 ≤ x < 45 7 7 50 = 0 . 14 45 ≤ x < 60 14 14 50 = 0 . 28 60 ≤ x < 75 20 20 50 = 0 . 4 Now plot the time spent on x - axis and relative frequency on y - axis to construct the Relative frequency histogram of data of men. Now plot the time spent on x - axis and relative frequency on y - axis to construct the Relative frequency histogram of data of women. The histogram for men is symmetrical as it has one prominent peak and equal tails to the left and the right and it is a unimodal distribution as we have only one peak. The histogram for women is centered mainly on the longer times and it is a unimodal distribution as we have only one peak.

The tables show the length of time some men and women spent on their mobile phones one day. Time spent in minutes (men) Frequency 0 ≤ x < 15 5 15 ≤ x < 30 8 30 ≤ x < 45 10 45 ≤ x < 60 5 60 ≤ x < 75 2 Time spent in minutes (women) Frequency 0 ≤ x < 15 4 15 ≤ x < 30 5 30 ≤ x < 45 7 45 ≤ x < 60 14 60 ≤ x < 75 20 Compare the length of time spent on the phone by the men and women.

Given data shows the length of time some men and women spent on their mobile phones one day. For a data set with n members or total frequency n , a class interval with frequency f has relative frequency f n . Now the relative frequency table for men whose total frequency is = 5 + 8 + 10 + 5 + 2 = 30 is given by Time spent in minutes (men) Frequency f Relative frequency 0 ≤ x < 15 5 5 30 = 0 . 16 15 ≤ x < 30 8 8 30 = 0 . 26 30 ≤ x < 45 10 10 30 = 0 . 33 45 ≤ x < 60 5 5 30 = 0 . 16 60 ≤ x < 75 2 2 30 = 0 . 06 Now the relative frequency table for women whose total frequency is = 4 + 5 + 7 + 14 + 20 = 50 is given by Time spent in minutes (women) Frequency f Relative frequency 0 ≤ x < 15 4 4 50 = 0 . 08 15 ≤ x < 30 5 5 50 = 0 . 1 30 ≤ x < 45 7 7 50 = 0 . 14 45 ≤ x < 60 14 14 50 = 0 . 28 60 ≤ x < 75 20 20 50 = 0 . 4 Now plot the time spent on x - axis and relative frequency on y - axis to construct the Relative frequency histogram of data of men. Now plot the time spent on x - axis and relative frequency on y - axis to construct the Relative frequency histogram of data of women. By comparing the length of time spent by men and women from graph, Women talked for longer on the phone than men. The spread of times is similar.

The tables show the masses of some male and female Siberian huskies. Mass, m in kg (Male Siberian husky) Frequency 17 ≤ m < 19 3 19 ≤ m < 21 6 21 ≤ m < 23 6 23 ≤ m < 25 11 25 ≤ m < 27 9 Mass, m in kg (Female Siberian husky) Frequency 17 ≤ m < 19 5 19 ≤ m < 21 8 21 ≤ m < 23 4 23 ≤ m < 25 2 25 ≤ m < 27 0 Calculate the relative frequency of each class interval as a percentage.

Given data show the masses of some male and female Siberian huskies. For a data set with n members or total frequency n , a class interval with frequency f has relative frequency f n . Now the relative frequency table for male whose total frequency is = 3 + 6 + 6 + 11 + 9 = 35 is given by Mass, m in kg (Male Siberian husky) Frequency ( f ) Relative frequency r [rounded off to two decimal places] Percentage r × 100 17 ≤ m < 19 3 3 35 = 0 . 09 9 19 ≤ m < 21 6 6 35 = 0 . 17 17 21 ≤ m < 23 6 6 35 = 0 . 17 17 23 ≤ m < 25 11 11 35 = 0 . 31 31 25 ≤ m < 27 9 9 35 = 0 . 26 26 Now the relative frequency table for female whose total frequency is = 5 + 8 + 4 + 2 + 0 = 19 is given by Mass, m in kg (Female Siberian husky) Frequency f Relative frequency r [rounded off to two decimal places] Percentage r × 100 17 ≤ m < 19 5 5 19 = 0 . 26 26 19 ≤ m < 21 8 8 19 = 0 . 42 42 21 ≤ m < 23 4 4 19 = 0 . 21 21 23 ≤ m < 25 2 2 19 = 0 . 11 11 25 ≤ m < 27 0 0 19 = 0 0

The tables show the masses of some male and female Siberian huskies. Mass, m in kg (Male Siberian husky) Frequency 17 ≤ m < 19 3 19 ≤ m < 21 6 21 ≤ m < 23 6 23 ≤ m < 25 11 25 ≤ m < 27 9 Mass, m in kg (Female Siberian husky) Frequency 17 ≤ m < 19 5 19 ≤ m < 21 8 21 ≤ m < 23 4 23 ≤ m < 25 2 25 ≤ m < 27 0 Draw relative frequency histograms for each data set.

Given data show the masses of some male and female Siberian huskies. For a data set with n members or total frequency n , a class interval with frequency f has relative frequency f n . Now the relative frequency table for male whose total frequency is = 3 + 6 + 6 + 11 + 9 = 35 is given by Mass, m in kg (Male Siberian husky) Frequency ( f ) Relative frequency r [rounded off to two decimal places] Percentage r × 100 17 ≤ m < 19 3 3 35 = 0 . 09 9 19 ≤ m < 21 6 6 35 = 0 . 17 17 21 ≤ m < 23 6 6 35 = 0 . 17 17 23 ≤ m < 25 11 11 35 = 0 . 31 31 25 ≤ m < 27 9 9 35 = 0 . 26 26 Now the relative frequency table for female whose total frequency is = 5 + 8 + 4 + 2 + 0 = 19 is given by Mass, m in kg (Female Siberian husky) Frequency f Relative frequency r [rounded off to two decimal places] Percentage r × 100 17 ≤ m < 19 5 5 19 = 0 . 26 26 19 ≤ m < 21 8 8 19 = 0 . 42 42 21 ≤ m < 23 4 4 19 = 0 . 21 21 23 ≤ m < 25 2 2 19 = 0 . 11 11 25 ≤ m < 27 0 0 19 = 0 0 Now plot the mass on x - axis and relative frequency as percentage on y - axis to construct the Relative frequency histogram of data of male. Now plot the mass on x - axis and relative frequency as percentage on y - axis to construct the Relative frequency histogram of data of female.

The tables show the masses of some male and female Siberian huskies. Mass, m in kg (Male Siberian husky) Frequency 17 ≤ m < 19 3 19 ≤ m < 21 6 21 ≤ m < 23 6 23 ≤ m < 25 11 25 ≤ m < 27 9 Mass, m in kg (Female Siberian husky) Frequency 17 ≤ m < 19 5 19 ≤ m < 21 8 21 ≤ m < 23 4 23 ≤ m < 25 2 25 ≤ m < 27 0 Comment on the distribution of the masses of the male and female Siberian huskies.

Given data show the masses of some male and female Siberian huskies. For a data set with n members or total frequency n , a class interval with frequency f has relative frequency f n . Now the relative frequency table for male whose total frequency is = 3 + 6 + 6 + 11 + 9 = 35 is given by Mass, m in kg (Male Siberian husky) Frequency ( f ) Relative frequency r [rounded off to two decimal places] Percentage r × 100 17 ≤ m < 19 3 3 35 = 0 . 09 9 19 ≤ m < 21 6 6 35 = 0 . 17 17 21 ≤ m < 23 6 6 35 = 0 . 17 17 23 ≤ m < 25 11 11 35 = 0 . 31 31 25 ≤ m < 27 9 9 35 = 0 . 26 26 Now the relative frequency table for female whose total frequency is = 5 + 8 + 4 + 2 + 0 = 19 is given by Mass, m in kg (Female Siberian husky) Frequency f Relative frequency r [rounded off to two decimal places] Percentage r × 100 17 ≤ m < 19 5 5 19 = 0 . 26 26 19 ≤ m < 21 8 8 19 = 0 . 42 42 21 ≤ m < 23 4 4 19 = 0 . 21 21 23 ≤ m < 25 2 2 19 = 0 . 11 11 25 ≤ m < 27 0 0 19 = 0 0 Now plot the mass on x - axis and relative frequency as percentage on y - axis to construct the Relative frequency histogram of data of male. Now plot the mass on x - axis and relative frequency as percentage on y - axis to construct the Relative frequency histogram of data of female. Comparing the graphs, Male huskies tend to weigh more than female huskies. The spread is narrower for the female huskies and male. The distribution for the females is fairly symmetrical. Both are unimodal as they have only one peak.

Rose Harrison and Clara Huizink Solutions for Exercise 11: Practice 4

Author:Rose Harrison & Clara Huizink

Rose Harrison Mathematics Solutions for Exercise - Rose Harrison and Clara Huizink Solutions for Exercise 11: Practice 4

Attempt the practice questions from Exercise 11: Practice 4 with hints and solutions to strengthen your understanding. MYP Mathematics A concept based approach 4&5 Standard solutions are prepared by Experienced Embibe Experts.

Questions from Rose Harrison and Clara Huizink Solutions for Exercise 11: Practice 4 with Hints & Solutions

EASY

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 4>Q 1

The tables show the length of time some men and women spent on their mobile phones one day.

Time spent in minutes (men)	Frequency
$0 \leq x < 15$	$5$
$15 \leq x < 30$	$8$
$30 \leq x < 45$	$10$
$45 \leq x < 60$	$5$
$60 \leq x < 75$	$2$

Time spent in minutes (women)	Frequency
$\frac{5}{50} = 0.1$	$4$
$15 \leq x < 30$	$5$
$30 \leq x < 45$	$7$
$45 \leq x < 60$	$14$
$60 \leq x < 75$	$20$

Calculate the relative frequencies for each class interval.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 4>Q 1

The tables show the length of time some men and women spent on their mobile phones one day.

Time spent in minutes (men)	Frequency
$0 \leq x < 15$	$5$
$15 \leq x < 30$	$8$
$30 \leq x < 45$	$10$
$45 \leq x < 60$	$5$
$60 \leq x < 75$	$2$

Time spent in minutes (women)	Frequency
$0 \leq x < 15$	$4$
$15 \leq x < 30$	$5$
$30 \leq x < 45$	$7$
$45 \leq x < 60$	$14$
$60 \leq x < 75$	$20$

Draw relative frequency histograms for the two sets of data.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 4>Q 1

The tables show the length of time some men and women spent on their mobile phones one day.

Time spent in minutes (men)	Frequency
$0 \leq x < 15$	$5$
$15 \leq x < 30$	$8$
$30 \leq x < 45$	$10$
$45 \leq x < 60$	$5$
$60 \leq x < 75$	$2$

Time spent in minutes (women)	Frequency
$0 \leq x < 15$	$4$
$15 \leq x < 30$	$5$
$30 \leq x < 45$	$7$
$45 \leq x < 60$	$14$
$60 \leq x < 75$	$20$

Describe each distribution.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 4>Q 1

The tables show the length of time some men and women spent on their mobile phones one day.

Time spent in minutes (men)	Frequency
$0 \leq x < 15$	$5$
$15 \leq x < 30$	$8$
$30 \leq x < 45$	$10$
$45 \leq x < 60$	$5$
$60 \leq x < 75$	$2$

Time spent in minutes (women)	Frequency
$0 \leq x < 15$	$4$
$15 \leq x < 30$	$5$
$30 \leq x < 45$	$7$
$45 \leq x < 60$	$14$
$60 \leq x < 75$	$20$

Compare the length of time spent on the phone by the men and women.

EASY

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 4>Q 2

The tables show the masses of some male and female Siberian huskies.

Mass, $m$ in $kg$ (Male Siberian husky)	Frequency
$17 \leq m < 19$	$3$
$19 \leq m < 21$	$6$
$21 \leq m < 23$	$6$
$23 \leq m < 25$	$11$
$25 \leq m < 27$	$9$

Mass, $m$ in $kg$ (Female Siberian husky)	Frequency
$17 \leq m < 19$	$5$
$19 \leq m < 21$	$8$
$21 \leq m < 23$	$4$
$23 \leq m < 25$	$2$
$25 \leq m < 27$	$0$

Calculate the relative frequency of each class interval as a percentage.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 4>Q 2

The tables show the masses of some male and female Siberian huskies.

Mass, $m$ in $kg$ (Male Siberian husky)	Frequency
$17 \leq m < 19$	$3$
$19 \leq m < 21$	$6$
$21 \leq m < 23$	$6$
$23 \leq m < 25$	$11$
$25 \leq m < 27$	$9$

Mass, $m$ in $kg$ (Female Siberian husky)	Frequency
$17 \leq m < 19$	$5$
$19 \leq m < 21$	$8$
$21 \leq m < 23$	$4$
$23 \leq m < 25$	$2$
$25 \leq m < 27$	$0$

Draw relative frequency histograms for each data set.

MEDIUM

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 4>Q 2

The tables show the masses of some male and female Siberian huskies.

Mass, $m$ in $kg$ (Male Siberian husky)	Frequency
$17 \leq m < 19$	$3$
$19 \leq m < 21$	$6$
$21 \leq m < 23$	$6$
$23 \leq m < 25$	$11$
$25 \leq m < 27$	$9$

Mass, $m$ in $kg$ (Female Siberian husky)	Frequency
$17 \leq m < 19$	$5$
$19 \leq m < 21$	$8$
$21 \leq m < 23$	$4$
$23 \leq m < 25$	$2$
$25 \leq m < 27$	$0$

Comment on the distribution of the masses of the male and female Siberian huskies.

EASY

MYP:4-5

IMPORTANT

MYP Mathematics A concept based approach 4&5 Standard>Chapter 11 - City Skylines (Histograms)>Practice 4>Q 3

The histogram shows the relative frequency of items sold at different prices at a community fundraising event. There were $32$ items in total.

Question Image

Calculate how many items sold for less than $16$ dollars.

Rose Harrison and Clara Huizink Solutions for Exercise 11: Practice 4

Rose Harrison Mathematics Solutions for Exercise - Rose Harrison and Clara Huizink Solutions for Exercise 11: Practice 4

Questions from Rose Harrison and Clara Huizink Solutions for Exercise 11: Practice 4 with Hints & Solutions

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