RoseMarie Gallagher and Paul Ingram Solutions for Chapter: The Behaviour of Metals, Exercise 3: Q

Author:RoseMarie Gallagher & Paul Ingram

RoseMarie Gallagher Chemistry Solutions for Exercise - RoseMarie Gallagher and Paul Ingram Solutions for Chapter: The Behaviour of Metals, Exercise 3: Q

Attempt the free practice questions on Chapter 13: The Behaviour of Metals, Exercise 3: Q with hints and solutions to strengthen your understanding. Complete Chemistry for Cambridge IGCSE® Second Edition solutions are prepared by Experienced Embibe Experts.

Questions from RoseMarie Gallagher and Paul Ingram Solutions for Chapter: The Behaviour of Metals, Exercise 3: Q with Hints & Solutions

MEDIUM
Upper Secondary: IGCSE
IMPORTANT

What do you expect to happen when carbon powder is heated with calcium oxide?

MEDIUM
Upper Secondary: IGCSE
IMPORTANT

What do you expect to happen when carbon powder is heated with zinc oxide?

MEDIUM
Upper Secondary: IGCSE
IMPORTANT

Give the word equation when carbon powder is heated with calcium oxide.

MEDIUM
Upper Secondary: IGCSE
IMPORTANT

When chromium(III) oxide is heated with powdered aluminium, chromium and aluminium oxide form. Which is more reactive, chromium or aluminium?

EASY
Upper Secondary: IGCSE
IMPORTANT

Iron displaces copper from copper(II) sulphate solution. Explain what displaces means, in your own words.

MEDIUM
Upper Secondary: IGCSE
IMPORTANT

When copper wire is put into a colourless solution of silver nitrate, crystals of silver form on the wire, and the solution goes blue. Explain these changes.

EASY
Upper Secondary: IGCSE
IMPORTANT

Write the half equations, to show the electron transfer in the following reaction.

When the copper wire is put into a colourless solution of silver nitrate, crystals of silver form on the wire, and the solution goes blue. Explain these changes.

EASY
Upper Secondary: IGCSE
IMPORTANT

Write the ionic equations for the following reaction.

When the copper wire is put into a colourless solution of silver nitrate, crystals of silver form on the wire, and the solution goes blue. Explain these changes.