Simplify: 2 3 3 × 1 2 - 2 × 4 3 × 1 6 - 1

Given, 2 3 3 × 1 2 - 2 × 4 3 × 1 6 - 1 = 2 3 3 × 2 2 × 4 3 × 6 = 2 × 4 3 3 × 2 2 × 2 × 3 = 2 × 4 3 3 × 2 3 × 3 = 2 × 4 × 2 3 3 3 × 3 = 2 2 × 2 2 3 3 2 = 2 4 3 3 2 = 2 12 3 2 Hence, the answer is obtained.

Simplify: 5 - 1 × 8 - 1 2 × 4 3 3

Given, 5 - 1 × 8 - 1 2 × 4 3 3 Using the law of exponents, x - m = 1 x m , we get, = 1 5 × 1 8 2 × 4 3 3 = 1 5 2 × 1 2 3 2 × 2 2 3 3 3 = 1 5 2 × 1 2 6 × 2 6 3 3 = 1 5 2 × 3 3 Hence, the required answer is obtained.

Simplify: 3 8 - 2 × 4 5 - 3

Given, 3 8 - 2 × 4 5 - 3 Using the law of exponents, x - m = 1 x m , we get, = 8 3 2 × 5 4 3 = 64 9 × 125 64 = 125 9 Hence, the answer is obtained above.

Simplify: 1 2 - 2 + 1 3 - 2 + 1 4 - 2

Given, 1 2 - 2 + 1 3 - 2 + 1 4 - 2 We know that, x - m = 1 x m 1 2 - 2 = 2 2 , 1 3 - 2 = 3 2 , 1 4 - 2 = 4 2 Thus, 1 2 - 2 + 1 3 - 2 + 1 4 - 2 = 2 2 + 3 2 + 4 2 1 2 - 2 + 1 3 - 2 + 1 4 - 2 = 4 + 9 + 16 = 29 Therefore, the answer is 29 .

Simplify: 5 - 1 × 3 - 1 - 1 ÷ 6 - 1 2

Given, 5 - 1 × 3 - 1 - 1 ÷ 6 - 1 2 Using the law of exponents, x - m = 1 x m , we get, = 1 5 × 1 3 - 1 ÷ 1 6 2 = 1 15 - 1 ÷ 1 6 2 = 15 ÷ 1 6 2 = 15 1 6 2 = 15 × 6 2 = 90 2 = 8100 Hence, the answer is obtained above.

Simplify: - 1 3 - 3 - 1 2 - 2 ÷ 1 4 2

Given, - 1 3 - 3 - 1 2 - 2 ÷ 1 4 2 Let us simplify and find the answer. Using the law of exponents, x - m = 1 x m , we get, = - 3 3 - 2 2 ÷ 1 16 = - 27 - 4 ÷ 1 16 = - 31 1 16 = - 31 × 16 = - 496 Hence, the answer is obtained above.

Simplify: 8 - 3 × 4 4 × 7 0 × 6 2

Given, 8 - 3 × 4 4 × 7 0 × 6 2 Using the law of exponents, x - m = 1 x m , we get, = 1 8 3 × 4 4 × 7 0 × 6 2 Here, 8 can be written as 2 3 and 4 4 can be written as 2 2 × 2 2 . = 1 2 3 3 × 2 2 × 2 2 × 7 0 × 6 2 = 1 2 2 × 2 3 × 2 2 × 2 2 × 7 0 × 6 2 = 1 2 2 × 2 3 × 2 2 × 2 2 × 1 × 6 2 ∵ x 0 = 1 = 1 8 × 4 × 36 18 = 18 Hence, the answer is obtained above.

E M B I B E

'I Did It' Mathematics>Chapter 4 - Exponents>Exercise 4.1

Rupesh Pathak and Vaishali Bhatia Solutions for Chapter: Exponents, Exercise 2: Exercise 4.1

Author:Rupesh Pathak & Vaishali Bhatia

Rupesh Pathak Mathematics Solutions for Exercise - Rupesh Pathak and Vaishali Bhatia Solutions for Chapter: Exponents, Exercise 2: Exercise 4.1

Attempt the practice questions on Chapter 4: Exponents, Exercise 2: Exercise 4.1 with hints and solutions to strengthen your understanding. 'I Did It' Mathematics solutions are prepared by Experienced Embibe Experts.