Find the value of: - 10 - 10 ÷ - 10 - - 10 - 10

For simplification of numerical expressions, we follow the rule of BODMAS. This rule tells the order that we shall follow while simplifying. The order is given below: B - Brackets O - of D - Divide M - Multiply A - Add S - Subtract The given question is : - 10 - 10 ÷ - 10 - - 10 - 10 - 10 - 10 ÷ - 10 - - 10 - 10 = - 10 + - 10 ÷ - 10 - - 10 + - 10 = - 20 ÷ - 10 - - 20 = - 20 ÷ - 10 + 20 = - 20 ÷ 10 = - 20 10 = - 2 Hence, the value of - 10 - 10 ÷ - 10 - - 10 - 10 = - 2 .

Arrange - 9 ÷ 3 , - 4 + 6 , 2 - 4 , 1 - 7 - 3 , - 5 - 3 × 2 in ascending order.

Solve each one separately. - 9 ÷ 3 = - 9 3 = - 3 When you divide a negative number by a positive number then the quotient is negative. - 4 + 6 = 2 To get the sum of a negative and a positive number, use the sign of the larger number and subtract. 2 - 4 = - 8 The product of a positive integer and a negative integer is negative. 1 - 7 - 3 The absolute value of a number refers to the distance of a number from the origin of a number line. It is represented as | a | , which defines the magnitude of any integer ‘ a ’ . The absolute value of any integer, whether positive or negative, will be the real number, regardless of which sign it has. It is represented by two vertical lines | a | , which is known as the modulus of a . For example: 5 is the absolute value for both 5 and - 5 . 1 - 7 - 3 = 1 - 7 + - 3 = 1 - 10 = 1 × 10 = 10 - 5 - 3 × 2 Use BODMAS rule. - 5 - 3 × 2 = - 5 - 6 = - 5 + - 6 = - 11 Now, arranging them in ascending order by putting the smallest term on extreme left followed by the term greater to it. - 11 < - 8 < - 3 < 2 < 10 Therefore, the ascending order is: ⇒ - 5 - 3 × 2 < 2 - 4 < - 9 ÷ 3 < - 4 + 6 < 1 - 7 - 3

Add the additive inverse of - 12 + 16 - 42 ÷ 3 o f 7 to the product of - 2 , - 3 and - 4 .

For the simplification of numerical expressions, we follow the rule of BODMAS. This rule tells the order that we shall follow while simplifying. The order is given below: B - Brackets O - of D - Divide M - Multiply A - Add S - Subtract The given question is : Find the additive inverse of - 12 + 16 - 42 ÷ 3 o f 7 - 12 + 16 - 42 ÷ 3 o f 7 = - 12 + 16 - 42 ÷ 3 × 7 ⇒ - 12 + 16 - 14 × 7 = - 12 + 16 - 98 = - 12 + 16 + - 98 = 16 + - 110 = - 94 The additive inverse of an integer is obtained by changing the sign of the integer. Therefore, the additive inverse of - 94 is + 94 . Now add 94 to the product of - 2 , - 3 and - 4 . - 2 × - 3 × - 4 + 94 = 6 × - 4 + 94 = - 24 + 94 = 70 Hence, we get 70 when we add additive inverse of - 12 + 16 - 42 ÷ 3 o f 7 to the product of - 2 , - 3 and - 4 .

E M B I B E

Composite Mathematics For Class VII>Number System>Chapter 1 - Integers>Chapter Assessment

S K Gupta and Anubhuti Gangal Solutions for Exercise 7: Chapter Assessment

Author:S K Gupta & Anubhuti Gangal

S K Gupta Mathematics Solutions for Exercise - S K Gupta and Anubhuti Gangal Solutions for Exercise 7: Chapter Assessment

Attempt the free practice questions from Exercise 7: Chapter Assessment with hints and solutions to strengthen your understanding. Composite Mathematics For Class VII solutions are prepared by Experienced Embibe Experts.

Questions from S K Gupta and Anubhuti Gangal Solutions for Exercise 7: Chapter Assessment with Hints & Solutions

MEDIUM

7th CBSE

IMPORTANT

Composite Mathematics For Class VII>Chapter 1 - Integers>Chapter Assessment>Q 4

$(- 48) \times (- 1) \times 3 \times 0 \times (- 4) =$

HARD

7th CBSE

IMPORTANT

Composite Mathematics For Class VII>Chapter 1 - Integers>Chapter Assessment>Q 5

An elevator descends into a mine shaft at the rate of $6 m / \min$ . If the descent starts from $10 m$ above the ground level, how long will it take to reach - $350 m$ ?

HARD

7th CBSE

IMPORTANT

Composite Mathematics For Class VII>Chapter 1 - Integers>Chapter Assessment>Q 6

${(- 1)}^{217} \times {(- 4)}^{11} \times {(- 3)}^{13}$ results in a

HARD

7th CBSE

IMPORTANT

Composite Mathematics For Class VII>Chapter 1 - Integers>Chapter Assessment>Q 7

Aastha multiplied two numbers and got $- 4$ as the product. She then subtracted the second number from the first and got the answer as $5$ . The two numbers are :

HARD

7th CBSE

IMPORTANT

Composite Mathematics For Class VII>Chapter 1 - Integers>Chapter Assessment>Q 8

The product of three integers is $- 600$ . If two of them are $- 15$ and $10$ , the third integer is :

HARD

7th CBSE

IMPORTANT

Composite Mathematics For Class VII>Chapter 1 - Integers>Chapter Assessment>Q 9

Find the value of: $(- 10 - 10) \div \{- 10 - (- 10 - 10)\}$