S K Gupta and Anubhuti Gangal Solutions for Chapter: Cubes and Cube Roots, Exercise 1: Exercise 4

The value of $\sqrt[3]{392}\times \sqrt[3]{448}$.

The value of $\sqrt[3]{3379\times 729}$.

Find the smallest number by which $17496$ must be divided, so that the quotient is a perfect cube. Also find the cube root of the quotient. 

The digit in unit place of the cube of $47$.

The least possible value of $A$ for which $90\times A$ is a perfect cube is

$\sqrt[3]{5-\frac{10}{27}}$ is

$\sqrt[3]{-1728}+\sqrt{324}$ is

Evaluate:

$\sqrt[3]{\sqrt{0.000729}}+\sqrt[3]{0.008}$