1 . 56 g of sodium peroxide reacts with water according to the following equation, 2 Na 2 O 2 + 2 H 2 O → 4 NaOH + O 2 . Calculate volume of oxygen liberated at STP.

Given, Based on the reaction, two moles of sodium peroxide produce one mole of oxygen. i.e., 22 . 4 L . The weight of two moles of sodium peroxide is 2 × 2 × 23 + 2 × 16 = 156 g . The 156 g Na 2 O 2 gives = 22 . 4 L of oxygen. So, 1 . 56 g will give = 22 . 4 156 × 1 . 56 = 0 . 224 L .

Aluminium carbide reacts with water according to the following equation, Al 4 C 3 + 12 H 2 O → 4 Al ( OH ) 3 + 3 CH 4 . What mass of aluminium hydroxide is formed from 12 g of aluminium carbide?

Al 4 C 3 + 12 H 2 O → 4 Al ( OH ) 3 + 3 CH 4 . The molar mass of aluminium carbide is 4 × 27 + 3 × 12 = 144 g mol - 1 . One mole of aluminium carbide produces four moles of aluminium hydroxide. i.e., 4 × 27 + 3 × 16 + 1 = 312 g . So, 12 g of aluminium carbide produces = 2 . 17 × 12 = 26 g .

Aluminium carbide reacts with water according to the following equation. Al 4 C 3 + 12 H 2 O → 4 Al ( OH ) 3 + 3 CH 4 . What volume of methane s.t.p. is obtained from 12 g of aluminium carbide?

Al 4 C 3 + 12 H 2 O → 4 Al ( OH ) 3 + 3 CH 4 . The molar mass of aluminium carbide is 4 × 27 + 3 × 12 = 144 g mol - 1 . One mole of aluminium carbide produces three moles of methane. i.e., 3 × 22 . 4 = 67 . 2 L . So, 12 g of aluminium carbide produces = 67 . 2 144 × 12 = 5 . 6 L .

Nitrogen and hydrogen react to form ammonia. N 2 ( g ) + 3 H 2 ( g ) → 2 NH 3 ( g ) If 1000 g H 2 react with 2000 g of N 2 : Calculate the mass of ammonia( NH 3 ) that will be formed?

Nitrogen and hydrogen react to form ammonia. The reaction is given below, N 2 ( g ) + 3 H 2 ( g ) → 2 NH 3 ( g ) 28 g of nitrogen forms = 2 × 17 g NH 3 . 2000 g of nitrogen forms = 2428 . 6 g NH 3 . Therefore, the mass of ammonia is 2428 . 6 g .

E M B I B E

Selina Icse Concise Chemistry For Class 10>Chapter 5 - Mole Concept and Stoichiometry>EXERCISE-5D

S P Singh Solutions for Chapter: Mole Concept and Stoichiometry, Exercise 4: EXERCISE-5D

Author:S P Singh

S P Singh Chemistry Solutions for Exercise - S P Singh Solutions for Chapter: Mole Concept and Stoichiometry, Exercise 4: EXERCISE-5D

Attempt the practice questions on Chapter 5: Mole Concept and Stoichiometry, Exercise 4: EXERCISE-5D with hints and solutions to strengthen your understanding. Selina Icse Concise Chemistry For Class 10 solutions are prepared by Experienced Embibe Experts.

Questions from S P Singh Solutions for Chapter: Mole Concept and Stoichiometry, Exercise 4: EXERCISE-5D with Hints & Solutions

EASY

10th ICSE

IMPORTANT

Selina Icse Concise Chemistry For Class 10>Chapter 5 - Mole Concept and Stoichiometry>EXERCISE-5D>Q 8

$1.56 g$ of sodium peroxide reacts with water according to the following equation, $2 {Na}_{2} O_{2} + 2 H_{2} O \to 4 NaOH + O_{2}$ . Calculate volume of oxygen liberated at STP.

EASY

10th ICSE

IMPORTANT

Selina Icse Concise Chemistry For Class 10>Chapter 5 - Mole Concept and Stoichiometry>EXERCISE-5D>Q 8

$1.56 g$ of sodium peroxide reacts with water according to the following equation: $2 {Na}_{2} O_{2} + 2 H_{2} O \to 4 NaOH + O_{2}$ . Calculate mass of oxygen liberated.