S. L. Arora Solutions for Chapter: Wave Optics, Exercise 7: Problems For Practice

The light of wavelength $600 \mathrm{nm}$ is incident normally on a slit of width $3 \mathrm{mm}$. Calculate the linear width of central maximum on a screen kept $3 \mathrm{m}$ away from the slit

Light, of wavelength $500\mathrm{nm},$ falls, from a distant source, on a slit $0.50\mathrm{mm}$ wide. Distance between the two dark bands, on either side of the central bright band, of the diffraction pattern observed, on a screen placed $2\mathrm{m}$ from the slit in $\mathrm{mm}$ is 

A $0.02\mathrm{cm}$ wide slit is illuminated at normal incidence by light of wavelength $6000 \mathrm{\AA }$

Find the width of the central maximum band on the screen placed $1 \mathrm{m}$ away from the slit.

A Fraunhofer diffraction pattern due to a single slit of width $0.2 \mathrm{mm}$ is being obtained on a screen placed at a distance of $2 \mathrm{m}$ from the slit. The first minima lie at $5 \mathrm{mm}$ on either side of the central maximum on the screen. Find the wavelength of light used in angstrom.

A parallel beam of monochromatic light of wavelength $5000 \mathrm{\AA }$ is incident normally on a narrow slit of width $0.25 \mathrm{mm}.$ The diffraction pattern is observed on a screen placed at the focal plane of a convex lens placed close to the slit between slit and screen. Find the angular separation between the first secondary maxima on either side of the central maximum.

A screen is placed $50 \mathrm{cm}$ from a single slit which is illuminated with light of wavelength $6000 \mathrm{\AA }$. If the distance between the first and third minima in the diffraction pattern is $3.0 \mathrm{mm},$ width of the slit in $\mathrm{mm}$ is

Light of wavelength $5\times {10}^{-7} \mathrm{m}$ is diffracted by an aperture of width $2\times {10}^{-3} \mathrm{m}.$ For what distance in meter travelled by the diffracted beam does the spreading due to diffraction become greater than the width of the aperture?

A parallel beam of light of wavelength $600 \mathrm{nm}$ is incident normally on a slit of width 'd'. If the distance between the slits and the screen is $0.8 \mathrm{m}$ and the distance of $2\mathrm{nd}$ order minimum from the centre of the screen is $9.5 \mathrm{mm},$ calculate the width of the slit ?