Sarvesh K Verma Solutions for Chapter: Theory of Equations, Exercise 8: Practice Exercise

For $-3<\mathrm{x}<2$, find the range of $\mathrm{y}=-3{\mathrm{x}}^2+10\mathrm{x}-21$

The minimum and maximum values of $(7-x)^{2}-8$ are

The maximum value of $49-(7-\mathrm{x}{)}^2$ is:

The equation ${\mathrm{x}}^2-3(\mathrm{x}-3{)}^2-2=0$ has

A quadratic equation which attains its minimum $-4$ at $\mathrm{x}=5$ and its $\mathrm{y}$-intersect is $21,$ the largest root of this equation must be less than

A quadratic equation which attains its maximum $4$ at $\mathrm{x}=-4$, and $\mathrm{y}=3$ at $\mathrm{x}=-3$ what will be the value of equation at $\mathrm{x}=-5 ?$

A quadratic equation attains minimum at $\mathrm{x}=\frac{3}{2}$. Also, $\mathrm{y}=\frac{3}{4}$ at $\mathrm{x}=\frac{1}{2}$, what's the value of the equation when $\mathrm{x}=\frac{5}{2}?$

If one root of a quadratic equation is $-2$. At $\mathrm{x}=-5, \mathrm{y}=27$ and at $\mathrm{x}=7, \mathrm{y}=27$. Then what's the minimum value of the equation?