Seema Saini Solutions for Chapter: p-Block Group 17 (The Halogen Family), Exercise 2: DPP

Concentrated ${\mathrm{H}}_2{\mathrm{SO}}_4$ cannot be used to prepare $\mathrm{HBr}$ from $\mathrm{NaBr}$ because it

In the preparation of $\mathrm{HBr}$ or $\mathrm{HI}$, $NaX(\mathrm{X}=\mathrm{Br}, \mathrm{I})$ is treated with ${\mathrm{H}}_3{\mathrm{PO}}_4$ and not with concentrated ${\mathrm{H}}_2{\mathrm{SO}}_4$ because

Iodine reacts with hypo to give:

Select the correct order of acidity:

Hypoiodous acid is formed with:

Chlorine does not react with:

What oxidation state of $\mathrm{Cl}$ is observed, when ${\mathrm{Cl}}_2$ reacts with hot and concentrated $\mathrm{NaOH}$ solution?

If, ${\mathrm{Y}}_2$ in given reaction is ${\mathrm{Cl}}_2$ then $“\mathrm{X}"$ can be:

${\mathrm{Y}}_2+2{\mathrm{X}}^{-} \left(\mathrm{aq}\right)⟶2{\mathrm{Y}}^{-} \left(\mathrm{aq}\right)+{\mathrm{X}}_2$