Seema Saini Solutions for Chapter: Nuclear Chemistry, Exercise 1: DPP 6.1

What is the sequence of emission in this radioactive decay?
${{}_{\mathrm{Z}}{}^{\mathrm{A}}\mathrm{X}\to {}_{\mathrm{Z}+1}{}^{\mathrm{A}}\mathrm{Y} \to {}_{\mathrm{Z}-1}{}^{\mathrm{A}-4}\mathrm{Z} \to {}_{\mathrm{Z}-1}{}^{\mathrm{A}-4}\mathrm{Z}}^{*}$

Which of the following is an isodiapher of ${}_{92}{}^{235}\mathrm{U}$?

A certain radioactive material ${}_{\mathrm{Z}}{}^{\mathrm{A}}\mathrm{X}$ starts emitting $\mathrm{\alpha }$ and $\mathrm{\beta }$ particles successively such that the end product formed is ${}_{\mathrm{Z}-3}{}^{\mathrm{A}-8}\mathrm{Y}$. How many $\mathrm{\alpha }$ and $\mathrm{\beta }$ particles are emitted, respectively?

${}_{92}{}^{238}\mathrm{U} (\mathrm{III} \mathrm{B})$ undergoes the following emissions.
${}_{92}{}^{238}\mathrm{U}\stackrel{-\mathrm{\alpha }}{⟶}\mathrm{A}\stackrel{-\mathrm{\alpha }}{⟶}\mathrm{B}\stackrel{-\mathrm{\beta }}{⟶}\mathrm{C}$
Which of the following are correct?

In which of the following nuclear process the electrically neutral atom remains electrically neutral?

Which of the following are incorrect regarding the elimination of $\mathrm{\alpha }$ and $\mathrm{\beta }$ particles in forming an isodiapher?

A nuclide has a mass number $\left(\mathrm{A}\right)$ and atomic number $\left(\mathrm{Z}\right)$. During a radioactive process, when

$\left(\mathrm{a}\right)$ both $\mathrm{A}$ and $\mathrm{Z}$ decrease, the process is called $\mathrm{\alpha }-$decay.
$\left(\mathrm{b}\right)$ $\mathrm{A}$ remains unchanged and $\mathrm{Z}$ decreases by one unit, the process is called ${\mathrm{\beta }}^{+}$ or positron decay or $\mathrm{K}-$electron capture.
$\left(\mathrm{c}\right)$ both $\mathrm{A}$ and $\mathrm{Z}$ remain unchanged, the process is called $\mathrm{\gamma }-$decay.
$\left(\mathrm{d}\right)$ both $\mathrm{A}$ and $\mathrm{Z}$increase, the process is called nuclear isomerism.

Which of these options have a statement that is incorrect?

$\mathrm{A}\stackrel{-\mathrm{\alpha }}{⟶}\mathrm{B}\stackrel{-\mathrm{\alpha }}{⟶}\mathrm{C}\stackrel{-\mathrm{\beta }}{⟶}\mathrm{D}$

$\left(1\right)$ $\mathrm{A}$ and $\mathrm{B}$ are isobars.
$\left(2\right)$ $\mathrm{A}$ and $\mathrm{D}$ are isotopes.
$\left(3\right)$ $\mathrm{C}$ and $\mathrm{D}$ are isobars.
$\left(4\right)$ $\mathrm{A}$ and $\mathrm{C}$ are isotones.

Which of these options represents all incorrect statements for the decay process?