Seema Saini Solutions for Chapter: Thermodynamics, Exercise 4: DPP 5.4

Author:Seema Saini

Seema Saini Chemistry Solutions for Exercise - Seema Saini Solutions for Chapter: Thermodynamics, Exercise 4: DPP 5.4

Attempt the free practice questions on Chapter 5: Thermodynamics, Exercise 4: DPP 5.4 with hints and solutions to strengthen your understanding. Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced solutions are prepared by Experienced Embibe Experts.

Questions from Seema Saini Solutions for Chapter: Thermodynamics, Exercise 4: DPP 5.4 with Hints & Solutions

MEDIUM
JEE Main
IMPORTANT

Bond energies of F2 and Cl2 are 153.0 and 2424 kJ mol-1 respectively. The heat liberated in the reaction is 111.0 kJ Find out the bond energy of F-Cl.

1/2F2+1/2Cl2FCl

MEDIUM
JEE Main
IMPORTANT

The enthalpy of combustion of H2 (g) at 298 K to give H2O (g) is -249 kJ mol-1 and bond enthalpies of H-H and O=O are 433 kJ mol- and 492 kJ mol-1, respectively. What will be the bond enthalpy of O-H?

MEDIUM
JEE Main
IMPORTANT

Calculate ΔHro for the reaction CH2Cl2gCg+2Hg+2Clg. The average bond enthalpies of C-H and C-Cl bonds are 414 kJ mol-1 are 330 kJ mol-1.

HARD
JEE Main
IMPORTANT

Heat of hydrogenation of ethene is x1 and that of benzene is x2. Hence, what will be the resonance energy?

HARD
JEE Main
IMPORTANT

Using the data (all values in kJ mol-1 at 25°C) given below:

(A) Enthalpy of polymerization of ethylene =-72 kJ mol-1

(B) Enthalpy of formation of benzene (l)=49 kJ mol-1

(C) Enthalpy of vaporization of benzene (l)=144 kJ mol-1

(D) Resonance energy of benzene =-152 kJ mol-1

(E) Heat of formation of gaseous atoms from elements in their standard states H=218 kJ mol-1, C=715 kJ mol-1

(F) Average bond energy of C-H=415 kJ mol-1

What will be the bond energy of C-C and C=C respectively?

HARD
JEE Main
IMPORTANT

The average Xe-F bond energy is 34 kcal/mol, first I.E. of Xe is 279 kcal/mol, electron affinity of F is 85 kcal/mol and bond dissociation energy of F2 is 38 kcal/mol. Then, the enthalpy change for the reaction

XeF4Xe++F-+F2+F will be

HARD
JEE Main
IMPORTANT

If ΔHfoC2H6g=-85 kJ mol-1ΔHfoC3H8g=-104 kJ mol-1, ΔH°  for CsCg is 718 kJ mol-1 and heat of formation of H-atom is  218 kJ mol-1, then:

HARD
JEE Main
IMPORTANT

Enthalpy of atomisation of C2H6 g and C3H8 g are 620 kJ mol-1 and 880 kJ mol-1. Therefore,