NCERT Solutions for Chapter: Linear Equations in One Variable, Exercise 1: Exercise

A linear equation can be written as $ax+b=0$, where $a$ and $b$ are constants. Write the equation $3(x-1)=5(2x+1)$ in the form of $ax+b=0$.

Sasha solves a linear equation.

Her work is shown below.

$2x-3=\frac{x}{2}-5$

$2\left(2x-3\right)=x-5$...Step $1$

$4x-6=x-5$...Step $2$

$3x=1$...Step $4$

$x=\frac{1}{3}$

Is Sasha's solution correct? If not, in which step did Sasha make an error.

Solve the given equation and verify the solution.

$7x+5=3\left(x-2\right)-1$

In a quiz competition, each team was asked $20$questions. For every right answer, they scored $5$ points; for every wrong or no answer, $5$ points were deducted from their score. Team A scored $60$points in the competition. In how many questions did they go wrong or give no answer?

 Find the value of $P$ and check your answer:

$\frac{P+2}{3}+7= \frac{3P-8}{2}- P+1$

 Which of the following is true for the expression $2\sqrt{x}+9=17$?

If $\frac{y}{4}-\frac{1}{2}=\frac{y}{3}+1$, then value of $y$ is 

The solution of equation $\frac{2x-3}{2x+3}=\frac{2}{3}$ is