Reduce 12 52 to the simplest form.

To reduce the given fraction to its simplest fraction, we divide both numerator and denominator by the HCF of the given numbers. HCF is the highest common factor. The HCF of 12 and 52 is 4 . So, 12 52 = 3 13 Thus, the simplest form is 3 13 .

What is the value of 3 4 9 + 5 5 9 ?

First we need to express the given mixed fractions in the form of improper fractions. 3 4 9 = 3 9 + 4 9 = 31 9 5 5 9 = 5 9 + 5 9 = 50 9 Now we add 3 4 9 and 5 5 9 . That is, 3 4 9 + 5 5 9 = 31 9 + 50 9 = 31 + 50 9 = 81 9 = 9

Express 125 8 as mixed fraction.

To express the given improper fraction as mixed fraction, we divide the numerator by the denominator. When we divide the fraction, the quotient is 15 and remainder is 5 . Thus, 125 8 can be written as 15 5 8 .

Meena was given 3 5 of a lot of marbels. What fractions was left in the lot?

Given, Meena was given 3 5 of a lot of marbles. Therefore, marbles left in the lot = 1 - 3 5 = 5 - 3 5 = 2 5 Thus, the fraction of marbles left in the lot is 2 5 .

What is the equivalent fraction of 5 7 having denominator 56 ?

To make the denominator 56 we will multiply 7 by 8 . So, 5 7 = 5 × 8 7 × 8 = 40 56 The equivalent fraction of 5 7 having denominator 56 is 40 56 .

What is the value of 8 2 5 - 2 3 5 ?

First we express the given mixed fractions as improper fractions. That is, 8 2 5 = 8 ( 5 ) + 2 5 = 42 5 2 3 5 = 5 ( 2 ) + 3 5 13 5 Now, 8 2 5 – 2 3 5 = 42 5 - 13 5 = 42 - 13 5 = 29 5 = 5 4 5

E M B I B E

Mental Maths 6>Chapter 7 - Fractions>Exercise 1

Subject Experts Solutions for Chapter: Fractions, Exercise 1: Exercise 1

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Subject Experts Mathematics Solutions for Exercise - Subject Experts Solutions for Chapter: Fractions, Exercise 1: Exercise 1

Attempt the practice questions on Chapter 7: Fractions, Exercise 1: Exercise 1 with hints and solutions to strengthen your understanding. Mental Maths 6 solutions are prepared by Experienced Embibe Experts.