Tamil Nadu Board Solutions for Chapter: Mensuration, Exercise 18: Exercise 7.5
Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Mensuration, Exercise 18: Exercise 7.5
Attempt the free practice questions on Chapter 7: Mensuration, Exercise 18: Exercise 7.5 with hints and solutions to strengthen your understanding. Mathematics Standard 10 solutions are prepared by Experienced Embibe Experts.
Questions from Tamil Nadu Board Solutions for Chapter: Mensuration, Exercise 18: Exercise 7.5 with Hints & Solutions
The total surface area of a hemisphere is how many times the square of its radius

A solid sphere of radius is melted and cast into a shape of a solid cone of same radius. The height of the cone is

A frustum of a right circular cone is of height with radii of its ends as and . Then, the volume of the frustum is

A shuttlecock used for playing badminton has the shape of the combination of

A spherical ball of radius units is melted to make new identical spherical balls each of radii units. Then is

The volume (in ) of the greatest sphere that can be cut off from a cylindrical log of wood of base radius and height is

The height and radius of the cone of which the frustum is a part are units and units respectively. The height of the frustum is units and the radius of the smaller base is units. If , then is

The ratio of the volumes of a cylinder, a cone, and a sphere, if the lengths of diameter is equal to the height and diameters of all the shapes are equal is
