Tamil Nadu Board Solutions for Chapter: Numbers And Sequences, Exercise 35: Exercise 2.1

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Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Numbers And Sequences, Exercise 35: Exercise 2.1

Attempt the free practice questions on Chapter 2: Numbers And Sequences, Exercise 35: Exercise 2.1 with hints and solutions to strengthen your understanding. Mathematics Standard 10 solutions are prepared by Experienced Embibe Experts.

Questions from Tamil Nadu Board Solutions for Chapter: Numbers And Sequences, Exercise 35: Exercise 2.1 with Hints & Solutions

HARD
10th Tamil Nadu Board
IMPORTANT

The first term of an arithmetic progression is unity and the common difference is 4. Which of the following will be a term of this A.P. 

EASY
10th Tamil Nadu Board
IMPORTANT

If 6 times of 6th  term of an A.P is equal to 7 times the 7th term, then the 13th term of the A.P. is

MEDIUM
10th Tamil Nadu Board
IMPORTANT

An A.P consists of 31 terms. If its 16th term is m, then the sum of all the terms of this A.P. is

MEDIUM
10th Tamil Nadu Board
IMPORTANT

In an A.P., the first term is 1 and the common difference is 4. How many terms of the A.P must be taken for their sum to be equal to 120 ?

HARD
10th Tamil Nadu Board
IMPORTANT

If A=265 and B=264+263+262+....+20 which of the following is true?

EASY
10th Tamil Nadu Board
IMPORTANT

The next term of the sequence 316,18,112,118, is

EASY
10th Tamil Nadu Board
IMPORTANT

If the sequence t1, t2, t3,.. are in A.P. then the sequence t6, t12, t18, is

MEDIUM
10th Tamil Nadu Board
IMPORTANT

The value of 13+23+33++153-(1+2+3++15) is