Find the value of ( n + 3 ) ! ( n + 1 ) !

Given that ( n + 3 ) ! ( n + 1 ) ! We know that factorial of a natural number n is a product of first n natural numbers it is denoted by n ! i.e., n ! = n n - 1 n - 2 . . . . 3 2 1 . ∴ ( n + 3 ) ! ( n + 1 ) ! = ( n + 3 ) ( n + 2 ) ( n + 1 ) ! ( n + 1 ) ! = ( n + 3 ) ( n + 2 )

Evaluate n ! r ! ( n - r ) ! when For any n with r = 2 .

Given that, we have to evaluate n ! r ! n - r ! for any value of n with r = 2 . We know that factorial of a natural number n is a product of first n natural numbers it is denoted by n ! i.e., n ! = n n - 1 n - 2 . . . . 3 2 1 . ∴ n ! 2 ! ( n - 2 ) ! = n ( n - 1 ) ( n - 2 ) ! 2 ! ( n - 2 ) ! = n ( n - 1 ) 2 × 1 = n ( n - 1 ) 2

E M B I B E

Mathematics Standard 11 Vol I>Chapter 4 - Combinatorics and Mathematical Induction>Exercise

Tamil Nadu Board Solutions for Chapter: Combinatorics and Mathematical Induction, Exercise 1: Exercise

Author:Tamil Nadu Board

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Combinatorics and Mathematical Induction, Exercise 1: Exercise

Attempt the free practice questions on Chapter 4: Combinatorics and Mathematical Induction, Exercise 1: Exercise with hints and solutions to strengthen your understanding. Mathematics Standard 11 Vol I solutions are prepared by Experienced Embibe Experts.