Question

Arrange the following numbers in ascending order and descending order.

$33, 270; 1, 078; 137; 27, 935$

Accepted Answer

The given numbers are,

$33, 270; 1, 078; 137; 27, 935$

Count the number of digits. The number with least number of digits is the smallest and the number with more number of digits is the greatest.

So, the number of digits in first number is $5$ , second number is $4$ , third number is $3$ and fourth number is $5$ .

So, according to the digits of number the ascending order is $3 < 4 < 5$ and the descending order is $5 > 4 > 3$ .

Now there are two number with $5$ digits.

Comparing those numbers according to the place value digits:

Numbers TTh Th H T O

$33, 270$ $3$ $3$ $2$ $7$ $0$

$27, 935$ $2$ $7$ $9$ $3$ $5$

Now comparing the ten thousand digit we got: $2 < 3$ .

So, $27, 935 < 33, 270$ .

Now, the ascending order is $137 < 1, 078 < 27, 935 < 33, 270$ and the descending order is $33, 270 > 27, 935 > 1, 078 > 137$ .

Therefore, the answer of ascending order is $137; 1, 078; 27, 935; 33, 270$ and the descending order is $33, 270; 27, 935; 1, 078; 137$ .

Tamil Nadu Board Solutions for Chapter: Numbers, Exercise 9: Try this

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Numbers, Exercise 9: Try this

Questions from Tamil Nadu Board Solutions for Chapter: Numbers, Exercise 9: Try this with Hints & Solutions

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