Tamil Nadu Board Solutions for Chapter: Algebra, Exercise 21: Exercise 3.4

Factorise the following expressions using ${\left(a-b\right)}^3=a^3-3a^{2}b+3a{b}^2-b^3$ identity.

$y^3-18y^2+108y-216$

Factorise the following expressions using ${\left(a-b\right)}^3=a^3-3a^{2}b+3a{b}^2-b^3$ identity.

$8m^3-60m^{2}n+150m{n}^2-125n^3$

Factors of $9x^2+6xy$ are

$4-m^2$ can be factorised as

$\left(x+4\right) \text{and} \left(x-5\right)$ are the factors of

The factors of $x^2-5x+6 \text{are} \left(x-2\right) \left(x-p\right)$ then the value of $p$ is

The factors of $1-m^3$

One factor of $x^3+y^3$ is: