Given algebraic expression = ( 3 - a ) 2 Use the algebraic identity a - b 2 = a 2 - 2 a b + b 2 to expand the given expression. Compare 3 - a 2 with a - b 2 , we have a = 3 and b = a . Now, 3 - a 2 = 3 2 - 2 3 × a + a 2 ⇒ 3 - a 2 = 9 - 6 a + a 2 Hence, the expanded form of 3 - a 2 = 9 - 6 a + a 2

Given expression = 6 2 - x 2 Use the algebraic identity a 2 - b 2 = a + b a - b to expand the given algebraic expression. Compare 6 2 - x 2 with a 2 - b 2 , we have a = 6 and b = x . Now, 6 2 - x 2 = 6 + x 6 - x Hence, the expanded form of 6 2 - x 2 = 6 + x 6 - x

Standard Eight Mathematics>Chapter 3 - Algebra>Try these

Tamil Nadu Board Solutions for Chapter: Algebra, Exercise 13: Try these

Author:Tamil Nadu Board

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Algebra, Exercise 13: Try these

Attempt the free practice questions on Chapter 3: Algebra, Exercise 13: Try these with hints and solutions to strengthen your understanding. Standard Eight Mathematics solutions are prepared by Experienced Embibe Experts.