Divide: 3 x 2 y 3 by 6 x 2 y 3

Given, 3 x 2 y 3 by 6 x 2 y 3 As we know that a n m = a m n and a n ÷ a m = a n - m 3 x 2 y 3 = 3 3 × x 2 × 3 × y 3 = 3 3 x 6 y 3 Now, 3 3 x 6 y 3 6 x 2 y 3 = 3 3 × x 6 - 2 × y 3 - 3 6 = 9 x 2 6 Hence, the required answer is 9 x 2 6

Divide: 81 p 2 q 4 by 81 p 2 q 4

Given, 81 p 2 q 4 by 81 p 2 q 4 As we know that a n ÷ a m = a n - m Now, 81 p 2 q 4 81 p 2 q 4 = 3 4 × p 2 × q 4 3 × 3 × 3 × 3 × p × p × q × q × q × q = 3 4 × p 2 × q 4 3 × 3 × p × q × q = 3 4 × p 2 × q 4 3 2 × p × q 2 = 3 4 - 2 × p × q 4 - 2 = 3 2 × p × q 2 = 9 p q 2 Hence, the required answer is 9 p q 2

E M B I B E

Standard Eight Mathematics>Chapter 3 - Algebra>Try these

Tamil Nadu Board Solutions for Chapter: Algebra, Exercise 9: Try these

Author:Tamil Nadu Board

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Algebra, Exercise 9: Try these

Attempt the free practice questions on Chapter 3: Algebra, Exercise 9: Try these with hints and solutions to strengthen your understanding. Standard Eight Mathematics solutions are prepared by Experienced Embibe Experts.