Find the C.I for the data given below: Principal = ₹ 5000 , r = 4 % p.a, n = 1 1 2 years, interest compounded half-yearly.

Given, principal = ₹ 5000 , r = 4 % p.a, n = 1 1 2 years Amount, A = P 1 + r 200 2 n = 5000 1 + 4 200 2 × 3 2 = 5000 × 51 50 × 51 50 × 51 50 = 51 × 10 . 2 × 10 . 2 = ₹ 5306 . 04 ∴ C . I = A - P = ₹ 5306 . 04 - ₹ 5000 = ₹ 306 . 04 Hence, the required compound interest is ₹ 306 . 04 .

Find the C.I for the data given below: Principal = ₹ 10000 , r = 8 % p.a, n = 2 3 4 years, interest compounded yearly.

Given, principal = ₹ 10000 , r = 8 % p.a, n = 2 3 4 years. Amount, A = P 1 + r 100 a 1 + b c × r 100 = 10000 1 + 8 100 2 1 + 3 4 × 8 100 = 10000 27 25 2 53 50 = 10000 × 27 25 × 27 25 × 53 50 A = ₹ 12363 . 84 ∴ C . I = A - P = ₹ 12363 . 84 - ₹ 10000 = ₹ 2363 . 84 Hence, the required compound interest is ₹ 2363 . 84 .

E M B I B E

Standard Eight Mathematics>Chapter 4 - Life Mathematics>Example

Tamil Nadu Board Solutions for Chapter: Life Mathematics, Exercise 14: Example

Author:Tamil Nadu Board

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Life Mathematics, Exercise 14: Example

Attempt the free practice questions on Chapter 4: Life Mathematics, Exercise 14: Example with hints and solutions to strengthen your understanding. Standard Eight Mathematics solutions are prepared by Experienced Embibe Experts.