Tamil Nadu Board Solutions for Chapter: Life Mathematics, Exercise 8: Exercise 4.3

If the compound interest on $₹3200$ at$2.5 \% \mathrm{p}.\mathrm{a}$ for $2$ years, compounded annually is $₹k$, then find the value of $k$.

Find the compound interest for $2\frac{1}{2}$ years on $₹4000$ at $10 \% \mathrm{p}.\mathrm{a}$ if the interest is compounded yearly.

A principal becomes $₹2028$ in $2$ years at $4\% \mathrm{p}.\mathrm{a}$ compound interest. Find the Principal.

In how many years will $₹3375$ become $₹4096$ at $13\frac{1}{3}\%\mathrm{p}.\mathrm{a}$ where interest is compounded half-yearly? Express your answer in years.

If the $\mathrm{C}.\mathrm{I}$ on $₹15000$ for $3$ years when the rates of interest are $15\%,20\%$ and $25\%$ for $\mathrm{I}$, $\mathrm{II}$ and $\mathrm{III}$ years respectively is $₹k$, find $k$.

If the difference between $\mathrm{C}.\mathrm{I}$ and $\mathrm{S}.\mathrm{I}$ on $₹5000$ for $1$ year at $2 \% \mathrm{p}.\mathrm{a}$ is$₹k$, find $k$. Given that the interest is compounded half-yearly.

Find the rate of interest if the difference between $\mathrm{C}.\mathrm{I}$ and $\mathrm{S}.\mathrm{I}$ on $₹8000$ compounded annually for $2$ years is $₹20$.

Find the principal if the difference between$\mathrm{C}.\mathrm{I}$ and $\mathrm{S}.\mathrm{I}$at $15 \% \mathrm{p}.\mathrm{a}$ for $3$years is $₹1134$.