Umakant Kondapure, Collin Fernandes, Nipun Bhatia, Vikram Bathula and, Ketki Deshpande Solutions for Chapter: Magnetic Effect of Electric Current, Exercise 2: Critical Thinking

A cyclotron in which flux density is $1.4 \mathrm{T}$ is employed to accelerate protons. How rapidly should the field between the dees be reversed if mass of proton be taken as $1.6 \times 10^{-27} \mathrm{kg}$ ?

In a cyclotron, the time taken by ion to describe a semicircular path is $2.3 \times 10^{-8} \mathrm{s}$. The cyclotron frequency will be

The maximum kinetic energy of protons in a cyclotron of radius $0.4 \mathrm{m}$ in a magnetic field of $0.5 \mathrm{T}$ is (mass of proton $=1.67 \times 10^{-27} \mathrm{kg}$, charge of proton $\left.=1.6 \times 10^{-19} \mathrm{C}\right)$

A galvanometer with a scale divided into $150$ equal divisions has a current sensitivity of $10 \mathrm{div} {\mathrm{mA}}^{-1}$ and voltage sensitivity of $2 \mathrm{div} {\mathrm{mV}}^{-1}$. The shunt resistance to be connected to the galvanometer so that it can read a current of $6 \mathrm{A}$ will be

The ratio of the magnetic field at the centre of a current carrying circular wire and the magnetic field at the centre of a semi-circular coil made from the same length of wire will be

Two infinite length wires carry currents $8 \mathrm{A}$ and $6 \mathrm{A}$ and are placed along $X$ -axis and Y-axis respectively. Magnetic field at a point $\mathrm{P}(0,0, \mathrm{d}) \mathrm{m}$ will be

In an ammeter, $4 \%$ of the main current is passing through the galvanometer. If shunt resistance is $5 \Omega,$ then resistance of galvanometer will be

Assertion: In a shunted galvanometer, only $10 \%$ current passes through the galvanometer. The resistance of the galvanometer is $G$. Then the resistance of the shunt is $\frac{G}{9}$.

Reason: If $\mathrm{S}$ is the resistance of the shunt, then voltage across $S$ and $G$ is same.