Umakant Kondapure, Collin Fernandes, Nipun Bhatia, Vikram Bathula and, Ketki Deshpande Solutions for Chapter: Stationary Waves, Exercise 2: Critical Thinking

In Melde's experiment, if the length of the string and the tension are kept constant, then the number of loops in perpendicular position is

In Melde's experiment, a string of length $0.8 \mathrm{m}$ and mass $1.0 \mathrm{g}$, vibrates in $4$, segments when the tension in the string is $0.4 \mathrm{kg} \mathrm{wt}.$ The frequency of the fork is (in perpendicular position)

Assertion: Our ears cannot distinguish two notes, one produced by a violin and other by a sitar, if they have exactly the same intensity and the same frequency.

Reason: When a musical instrument is played, it produces a fundamental note which is accompanied by a number of overtones called harmonics.

In Melde's experiment, $3$ loops are obtained when the string is stretched by a mass of $6 \mathrm{gm}$. In order to get $2$, loops without changing the position of the fork, the weight to be added (in $\mathrm{gm})$ will be $\left(g=10 \mathrm{m} {\mathrm{s}}^{-2}\right)$

The tension of a stretched string is increased by $69 \%.$ In order to keep its frequency of vibration constant, its length must be increased by

Assertion: If the tension in the string is doubled, then frequency of fundamental node becomes two times.

Reason: According to law of tension, frequency$\propto {\left(\text{tension}\right)}^{\frac{1}{2}}$

A tuning fork of frequency $500 \mathrm{Hz}$, is sounded on a resonance tube. The first and second resonances are observed at $17 \mathrm{cm}$ and $52 \mathrm{cm}$, respectively. The velocity of sound, in $\mathrm{m} {\mathrm{s}}^{-1}$ is

In order to increase the frequency of transverse oscillations of a stretched wire by $50 \%$, its tension must be increased by