Factorise a 2 b - b 3 and using it, find the value of 101 2 × 100 - 100 3 .

Given that to factorise a 2 b - b 3 and using it, find the 101 2 × 100 - 100 3 . a 2 b - b 3 = b ( a 2 - b 2 ) = b ( a + b ) ( a - b ) Substituting a = 101 , b = 100 in the factorisation of a 2 b - b 3 we get, b ( a + b ) ( a - b ) = 100 × ( 101 + 100 ) × ( 101 - 100 ) = 100 × 201 × 1 = 20100 Hence, the required answer is 20100 .

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Explore Mathematics - 8>Chapter 5 - Division and Factor of Algebraic Expression>Exercise 5

Uttar Pradesh Board Solutions for Chapter: Division and Factor of Algebraic Expression, Exercise 7: Exercise 5

Author:Uttar Pradesh Board

Uttar Pradesh Board Mathematics Solutions for Exercise - Uttar Pradesh Board Solutions for Chapter: Division and Factor of Algebraic Expression, Exercise 7: Exercise 5

Attempt the free practice questions on Chapter 5: Division and Factor of Algebraic Expression, Exercise 7: Exercise 5 with hints and solutions to strengthen your understanding. Explore Mathematics - 8 solutions are prepared by Experienced Embibe Experts.