Name: Introduction to Find Square root of a Number
Uploaded: 2019-07-19
Duration: 16 min 7 s
Description: In this video, how to find Square Root of a Perfect and Non Perfect Square numbers with examples are discussed. The content in this video is helpful to solve the related problems on this topic.

Question

Observe following table carefully and fill in the blanks:

$x$	$x^{2}$	$\sqrt{x^{2}}$	$\pm x$
$0.3$	$0.09$	$\sqrt{0.09}$	$\pm 0.3$
$0.5$	$0.25$	_____	_____
$0.41$	$0.1681$	_____	$\pm 0.41$
$4.1$	_____	$\sqrt{16.81}$	_____
$7.5$	_____	$\sqrt{56.25}$	_____
$1.25$	$1.5625$	_____	_____

Accepted Answer

Given that,

$x$ $x^{2}$ $\sqrt{x^{2}}$ $\pm x$

$0.3$ $0.09$ $\sqrt{0.09}$ $\pm 0.3$

$0.5$ $0.25$ _____ _____

$0.41$ $0.1681$ _____ $\pm 0.41$

$4.1$ _____ $\sqrt{16.81}$ _____

$7.5$ _____ $\sqrt{56.25}$ _____

$1.25$ $1.5625$ _____ _____

Here we have the value of $x$ from this we can find $x^{2}, \sqrt{x^{2}},$ and square root value.

$\begin{matrix} x & x^{2} & \sqrt{x^{2}} & \pm x \\ 0.3 & 0.09 & \sqrt{0.09} & \pm 0.3 \\ 0.5 & 0.25 & \sqrt{0.25} & \pm 0.5 \\ 0.41 & 0.1681 & \sqrt{0.1681} & \pm 0.41 \\ 4.1 & 16.81 & \sqrt{16.81} & \pm 4.1 \\ 7.5 & 56.25 & \sqrt{56.25} & \pm 7.5 \\ 1.25 & 1.5625 & \sqrt{1.5625} & \pm 1.25 \end{matrix}$

Uttar Pradesh Board Solutions for Chapter: Square Roots, Exercise 10: Try :

Uttar Pradesh Board Mathematics Solutions for Exercise - Uttar Pradesh Board Solutions for Chapter: Square Roots, Exercise 10: Try :

Questions from Uttar Pradesh Board Solutions for Chapter: Square Roots, Exercise 10: Try : with Hints & Solutions

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