In the below figure, a line P Q is drawn through the vertex A and parallel to the side B C of △ A B C . What can you conclude from the result of ∠ a + ∠ b + ∠ c ?

The given figure is, Now, P Q ∥ B C , A B is a transversal. Therefore, ∠ P A B = ∠ A B C (Alternate interior angles) ⇒ ∠ b = ∠ p . . . 1 Now, P Q ∥ B C , A C is a transversal. Therefore, ∠ Q A C = ∠ A C B (Alternate interior angles) ⇒ ∠ c = ∠ q . . . 2 We know that, sum of all the angles on a straight line is equal to 180 ° . Therefore, ∠ a + ∠ p + ∠ q = 180 ° ∠ a + ∠ b + ∠ c = 180 ° ∠ p = ∠ b & ∠ q = ∠ c Therefore, ∠ a + ∠ b + ∠ c is equal to 180 ° . Hence, we can conclude that, the sum of all the angles of a triangle is 180 ° .

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CPA Maths - A Singapore Approach>Chapter 10 - Lines and Angles>EXERCISE

Vistor Chow wal keung | RC Yadav Solutions for Chapter: Lines and Angles, Exercise 2: EXERCISE

Author:Vistor Chow wal keung | RC Yadav

Vistor Chow wal keung | RC Yadav Mathematics Solutions for Exercise - Vistor Chow wal keung | RC Yadav Solutions for Chapter: Lines and Angles, Exercise 2: EXERCISE

Attempt the free practice questions on Chapter 10: Lines and Angles, Exercise 2: EXERCISE with hints and solutions to strengthen your understanding. CPA Maths - A Singapore Approach solutions are prepared by Experienced Embibe Experts.