Question

Write what happened in the following reactions in the table below. State which one is oxidation and which one is reduction.

Equations of the reactions	What happened	Oxidation or reduction
(i) ${Fe}^{3 +} + e^{-} \to {Fe}^{2 +}$
(ii) ${Cl}^{-} \to Cl + e^{-}$
(iii) ${MnO}_{4}^{2 -} \to {MnO}_{4}^{-} + e^{-}$
(iv) ${Cu}^{2 +} + 2 e^{-} \to Cu$

Accepted Answer

Completed table is:

Equations of the reactions What happened Oxidation or reduction

(i) ${Fe}^{3 +} + e^{-} \to {Fe}^{2 +}$ Here, ${Fe}^{3 +}$ accepts one electron and forms ${Fe}^{2 +}$ . Reduction

(ii) ${Cl}^{-} \to Cl + e^{-}$ In this reaction, ${Cl}^{-}$ eliminates electron and forms chlorine atom. Oxidation

(iii) ${MnO}_{4}^{2 -} \to {MnO}_{4}^{-} + e^{-}$ In this reaction, ${MnO}_{4}^{2 -}$ eliminate electron and forms ${MnO}_{4}^{-}$ . Oxidation

(iv) ${Cu}^{2 +} + 2 e^{-} \to Cu$ In this reaction, ${Cu}^{2 +}$ accepts two electrons and form copper atom. Reduction

West Bengal Board Solutions for Chapter: Element, Compound and Chemical Reaction, Exercise 14: Exercise 14

West Bengal Board Science Solutions for Exercise - West Bengal Board Solutions for Chapter: Element, Compound and Chemical Reaction, Exercise 14: Exercise 14

Questions from West Bengal Board Solutions for Chapter: Element, Compound and Chemical Reaction, Exercise 14: Exercise 14 with Hints & Solutions

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