Arrange the given decimals in the ascending order. 0 . 3 ¯ , 0 . 1 6 ¯ , 0 . 1 ¯

Given recurring decimals are 0 . 3 ¯ , 0 . 1 6 ¯ , 0 . 1 ¯ ∴ 0 . 3 ¯ = 0 . 333333 . . . . . . , 0 . 1 6 ¯ = 0 . 1666666 . . . . . . . . , 0 . 1 ¯ = 0 . 111111 . . . . . . . First, let us compare the digits of tenth's place, In 0 . 3 ¯ , 3 is the digit in tenth's place, 0 . 1 6 ¯ has 1 as a tenth's place and 1 is the tenth's place digit in 0 . 1 ¯ . So, 0 . 3 ¯ is the greatest, since it's tenths place digit is greater than tenths place digit in the other two decimals. Now, let us compare hundredth's place digits of 0 . 1 6 ¯ and 0 . 1 ¯ . 0 . 1 6 ¯ has 6 in its hundredth's place and 0 . 1 ¯ has 1 in its hundredth's place. So, 0 . 1 6 ¯ is greater than 0 . 1 ¯ , since 6 is greater than 1 . Hence, the ascending order of the given decimals is 0 . 1 ¯ < 0 . 1 6 ¯ < 0 . 3 ¯ .

Arrange the given decimals in the ascending order. 0 . 63 ¯ , 5 6 , 3 4

Given recurring decimals are 0 . 63 ¯ , 5 6 , 3 4 ∴ 0 . 63 ¯ = 0 . 636363 . . . . . . , 5 6 = 0 . 833333 . . . . . . . . , 3 4 = 0 . 75 First, let us compare the digits of tenth's place, In 0 . 63 ¯ , 3 is the digit in tenth's place, 0 . 8 3 ¯ has 8 as a tenth's place and 7 is the tenth's place digit in 0 . 75 . So, 3 < 7 < 8 Hence, the ascending order of the given decimals is 0 . 63 ¯ < 3 4 < 5 6 .

Arrange the given decimals in the ascending order. 0 . 5 3 ¯ , 2 25 , 16 75

Given recurring decimals are 0 . 3 ¯ , 0 . 1 6 ¯ , 0 . 1 ¯ ∴ 0 . 5 3 ¯ = 0 . 5333333 . . . . . . , 2 25 = 0 . 08 , 16 75 = 0 . 2133 . . . . . . . . . . . First, let us compare the digits of tenth's place, In 0 . 5 3 ¯ , 5 is the digit in tenth's place, 0 . 08 has 0 as a tenth's place and 2 is the tenth's place digit in 0 . 2133 . . . . . . . So, 0 < 2 < 5 Hence, the ascending order of the given decimals is 2 25 < 16 75 < 0 . 3 ¯ .

Arrange the given decimals in the ascending order. 0 . 91 6 ¯ , 1 121 , 3 44

Given recurring decimals are 0 . 91 6 ¯ , 1 121 , 3 44 ∴ 0 . 91 6 ¯ = 0 . 91666666 . . . . . . , 1 121 = 0 . 0082644 . . . . . . , 3 44 = 0 . 06 81 ¯ First, let us compare the digits of tenth's place, In 0 . 91 6 ¯ , 5 is the digit in tenth's place, 0 . 0082644 . . . . . . has 0 as a tenth's place and 0 is the tenth's place digit in 0 . 06 81 ¯ So, 0 . 91 6 ¯ is the greatest among the given decimal numbers. Now, in 0 . 0082644 . . . . . . , 0 is the digit in hundredth's place and in 0 . 06 81 ¯ , 6 is the digit in hundredth's place. So, 0 . 06 81 ¯ > 0 . 0082644 . . . . . . Hence, the ascending order of the given decimals is 1 121 < 3 44 < 0 . 91 6 ¯ .

E M B I B E

GANITPRABHA (MATHEMATICS TEXT BOOK) CLASS 6>Chapter 10 - Recurring Decimal Number>Let's work out - 10

West Bengal Board Solutions for Chapter: Recurring Decimal Number, Exercise 10: Let's work out - 10

Author:West Bengal Board

West Bengal Board Mathematics Solutions for Exercise - West Bengal Board Solutions for Chapter: Recurring Decimal Number, Exercise 10: Let's work out - 10

Attempt the practice questions on Chapter 10: Recurring Decimal Number, Exercise 10: Let's work out - 10 with hints and solutions to strengthen your understanding. GANITPRABHA (MATHEMATICS TEXT BOOK) CLASS 6 solutions are prepared by Experienced Embibe Experts.