The potential difference between points $A$ and $B$ as shown in the figure is $16 \mathrm{V}$. Then,

In the circuit shown,the cell has emf $10 \mathrm{V}$ and internal resistance $1 \mathrm{\Omega }$.

When some potential difference is maintained between $A$ and $B,$ current $I$ enters the network at $A$ and leaves at $B$ (see figure).

In the circuit shown in figure, some potential difference is applied between $A\text{ and} B$. The equivalent resistance between $A \text{and }B$ is $R$.

A battery of emf $E$ and internal resistance $r$ is connected across a resistance $R.$ Resistance $R$ can be adjusted to any zero. A graph is plotted between the current passing through the resistance $\left(I\right)$ and potential difference $\left(V\right)$ across it. Select the correct alternatives.

In the given circuit (figure),

In the circuit shown in figure,mark the correct options.

In the given circuit (as shown in figure),

Study the following circuit diagrams in figures and select the correct options.