MEDIUM
JEE Main/Advance
IMPORTANT
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When will this capacitor get maximum charge, and what will be values of maximum charge and current at that state of the circuit?

Important Questions on Current Electricity

HARD
JEE Main/Advance
IMPORTANT

For the given arrangement shown in figure. The switch is closed at t=0 The time after which the current becomes 2.5μA is

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MEDIUM
JEE Main/Advance
IMPORTANT
A capacitor charges from a cell through a resistance the time constant is T. In what time will the capacitor collect 10% of its final charge?
MEDIUM
JEE Main/Advance
IMPORTANT
The charge on a capacitor decreases to n times of its initial value in time t, when it discharges through a circuit with a time constant T. The relation between t and T would be:
MEDIUM
JEE Main/Advance
IMPORTANT

In the circuit shown in the figure

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Capacitor C1 is charged to a potential of V. The current in the circuit just after the switch S is closed

HARD
JEE Main/Advance
IMPORTANT
When the capacitor is fully charged, work done by cell is W=n1×CV2, the energy stored in the capacitor is U=n2×CV2 and the heat produced across resistor is, H=n3×CV2. Then the values of n1, n2 & n3 are respectively
MEDIUM
JEE Main/Advance
IMPORTANT

Find charge on capacitor in steady state.

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EASY
JEE Main/Advance
IMPORTANT

If at t=0key'K is pressed then find maximum current in the circuit if initially charge on capacitor is zero.

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MEDIUM
JEE Main/Advance
IMPORTANT

In the four circuits, the time constant are τ1=CR, τ2=4CR, τ3=CR4, τ4=CR

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then