If a system is at equilibrium, the relation between rate of forward to the rate of reverse reaction is

Graph of a reversible process;

${\mathrm{N}}_2+3{\mathrm{H}}_2 \stackrel{}{\rightleftharpoons } 2{\mathrm{NH}}_3+\mathrm{Heat}$

is given. Analyse the graph and answer the following question.

Identify the part of the graph which represents the forward reaction

[ OA, BA, AC]

Graph of a reversible process;

is given. Analyse the graph and answer the following question.

Identify the part of the graph which represents the equilibrium state?

The reaction

${\mathrm{CaCO}}_3\left(\mathrm{s}\right)\rightleftharpoons \mathrm{CaO}\left(\mathrm{s}\right)+{\mathrm{CO}}_2\left(\mathrm{g}\right)$

is in equilibrium in a closed vessel at $298 \mathrm{K}.$ The partial pressure (in atm) of ${\mathrm{CO}}_2\left(\mathrm{g}\right)$ in the reaction vessel is closest to:

[Given: The change in Gibbs energies of formation at $298 \mathrm{K}$ and $1$ bar for

$\mathrm{CaO}\left(\mathrm{s}\right)=-603.501 \mathrm{kJ} {\mathrm{mol}}^{-1}$

${\mathrm{CO}}_2\left(\mathrm{g}\right)=-394.389 \mathrm{kJ} {\mathrm{mol}}^{-1}$

${\mathrm{CaCO}}_3\left(\mathrm{s}\right)=-1128.79 \mathrm{kJ} {\mathrm{mol}}^{-1}$

Gas constant $\mathrm{R}=8.314 \mathrm{J} {\mathrm{K}}^{-1} {\mathrm{mol}}^{-1}$]

Using the data provided, find the value of equilibrium constant for the following reaction at $298 \mathrm{K}$ and $1$ atm pressure. ${\mathrm{NO}}_{\left(\mathrm{g}\right)}+\frac{1}{2}{\mathrm{O}}_2( \mathrm{g})\rightleftharpoons {\mathrm{NO}}_2( \mathrm{g})$
${\mathrm{\Delta }}_{\mathrm{f}}{\mathrm{H}}^0\left({\mathrm{NO}}_{\left(\mathrm{g}\right)}\right)=90.4\mathrm{kJ}.{\mathrm{mol}}^{-1}$

${\mathrm{\Delta }}_{\mathrm{f}}{\mathrm{H}}^0\left({\mathrm{NO}}_2\left(\mathrm{g}\right)\right)=32.48\mathrm{kJ}\cdot {\mathrm{mol}}^{-1}$

${\mathrm{\Delta S}}^{\circ }\mathrm{at} 298\mathrm{K}=-70.8\mathrm{J}\cdot {\mathrm{K}}^{-1}\cdot {\mathrm{mol}}^{-1}$

$\mathrm{antilog}(0.50)=3162$

The value of ${\mathrm{K}}_{\mathrm{c}} \mathrm{us} 64 \mathrm{at} 800 \mathrm{K}$ for the reaction

${\mathrm{N}}_2\left(\mathrm{g}\right)+3{\mathrm{H}}_2\left(\mathrm{g}\right)\to 2 {\mathrm{NH}}_3 \left(\mathrm{g}\right)$

The value of ${\mathrm{K}}_{\mathrm{c}}$ for the following reaction is :

${\mathrm{NH}}_3 \left(\mathrm{g}\right)\to \frac{1}{2} {\mathrm{N}}_2 \left(\mathrm{g}\right)+\frac{3}{2} {\mathrm{H}}_2 \left(\mathrm{g}\right)$

Which of the following statement is correct about chemical equilibrium?

(i) At equilibrium both the reactants and products coexist.

(ii) At equilibrium rate of forward reaction is greater than the rate of backward reaction.

Graph of a reversible process,

is given. Analyse the graph and answer the following question.

From the given statements, select the correct ones regarding chemical equilibrium.

(i0 The chemical equilibrium is 'static' at the molecular level.

(ii) Both reactants and products co-exist.

(iii) The rates of forward reaction and backward reactions are equal.

(iv) Chemical equilibrium is attained in an open system.

Briefly explain the following:

Dynamic nature of chemical equilibrium