Rearranged Carbocation $+\mathrm{AgBr}$

The rearranged Carbocation is

The product $\mathrm{X} \& \mathrm{Y}$ respectively are.

When trans$-3-$Methyl$-2,3-$epoxy pentane treated with aqueous acid:

  trans$-3-$Methyl$-2,3-$epoxy pentane

Which of the following is/are correct regarding the given reaction?

In the given reaction, the percentage of $(-)$ enantiomer formed is:

$$\begin{gathered} {\mathrm{CH}}_3-\mathrm{CHI}-{\mathrm{CH}}_2-{\mathrm{CH}}_3\stackrel{{\mathrm{I}}^{-}}{⟶}{\mathrm{CH}}_3-\mathrm{CHI}-{\mathrm{CH}}_2{\mathrm{CH}}_3 \\ {\left(\mathrm{\alpha }\right)}_{\mathrm{obs}}=-15.90° {\left(\mathrm{\alpha }\right)}_{\mathrm{obs}}=-15.26° \end{gathered}$$