$-1000000$ is a perfect cube.

The cube root of$27\times 8$ is $6$ 

The least number amongst ${\left(0.5\right)}^2, \sqrt{0.49}, \sqrt[3]{0.008}, 0.28$ is $\left(0.5^2\right)$.

The least number that has to be added to $110$to make it a perfect cube is $25$.

The cube root of $-1.331$ is $-0.11$

The cube root of $0.000512$ is

$\sqrt[3]{\sqrt{0.000064}}=?$

The largest four digit number which is a perfect cube is

$\sqrt[3]{\frac{-125}{81}}=?$