Beta Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>EXERCISE-I (Conceptual Questions)>Q 69

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Which one of the following species will give a series of spectral lines similar to that of ${Mg}^{2 +}$ ?

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Important Questions on Structure of Atom

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Beta Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>EXERCISE-I (Conceptual Questions)>Q 70

The ratio of the minimum wavelength of the Lyman and Balmer series will be.

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Beta Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>EXERCISE-I (Conceptual Questions)>Q 71

The wavelength of photon obtained by the electron transition between the two levels in

H -

atom and singly ionised

He

are

λ_{1}

and

λ_{2}

, respectively, then:-

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Beta Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>EXERCISE-I (Conceptual Questions)>Q 72

Find out the ratio of the following for photons:

${(v_{\max})}_{Lyman} : {(v_{max})}_{Brakett}$

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Beta Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>EXERCISE-I (Conceptual Questions)>Q 73

The ratio of wavelengths of the first line of Lyman series in

{Li}^{+ 2}

and the first line of Lyman series in deuterium

({}_{1}^{2}H)

is :

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Beta Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>EXERCISE-I (Conceptual Questions)>Q 74

In an electronic transition, the atom cannot emit:-

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Beta Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>EXERCISE-I (Conceptual Questions)>Q 75

The first Lyman transition in the hydrogen spectrum has

ΔE = 10.2 eV

. The same energy change is observed in the second Balmer transition of:-

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Beta Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>EXERCISE-I (Conceptual Questions)>Q 76

The limiting line in the Balmer series will have a frequency of:

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Beta Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>EXERCISE-I (Conceptual Questions)>Q 77

If the shortest wavelength of the Lyman series of

H

atom is

x

, then the wavelength of the first line of the Balmer series of

H

atom will be: