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0.1 M solution of a weak base BOH has a pH of 8 when it is half neutralized with 0.1 M HNO3. The value of Kb of the base is:

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Important Questions on Equilibrium

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100 ml of 0.1 M of acetic acid, (pKa=5.1) is titrated against 100 ml of 0.1 M ammonia solution pKb=5.1 the pH of solution at equivalence point at 0°CpKw=15 is:
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The pH of solution in which equal volume of 0.1 M NaCN and 0.05 M HCl are added is; (pKa of HCN=6)

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200 ml of 0.1 M CH3COOH is mixed with 200 ml of 0.1 M NaOH. The resulting solution 
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On adding a catalyst to a reversible reaction,
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At the temperature T, a compound AB2 (g) dissociates, according to the reaction 2AB2 g2AB g+B2 g with a degree of dissociation x, which is small compared with unity. The expression for Kp in terms of x and the total pressure, P is
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X2+X-  X3- (X=Iodine)

This reaction is set up in an aqueous medium. The reaction started with 1 mol of X2 and 0.5 mol of X- in a 1 L flask. After equilibrium is reached, the excess AgNO3 gave 0.25 mol of yellow precipitate. The equilibrium constant is:

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One mole of N2O4g at 300 K is kept in a closed vessel at 1 atm pressure. It is heated to 600 K when 20% by mass of N2O4g decomposes to NO2g. The resultant pressure is:
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For the reaction equilibrium, 2NOBrg2NOg+Br2g, if PBr2=P9 at equilibrium and P is total pressure, then the ratio KPP is equal to: (assume that equilibrium was achieved starting with only NOBr)