MEDIUM
JEE Main/Advance
IMPORTANT
Earn 100

0.16 g of methane was subjected to combustion at 27°C in a bomb calorimeter. The temperature of calorimeter system (including water) was found to rise by 0.5°C. Calculate the heat of combustion of methane at constant pressure (in kJ mol-1).

The thermal capacity of calorimeter system is 17.7 kJ K-1R=8.313 mol-1 K-1

50% studentsanswered this correctly

Important Questions on Thermodynamics

MEDIUM
JEE Main/Advance
IMPORTANT
When 1.0 g of fructose C6H12O6s is burnt in oxygen in a bomb calorimeter, the temperature of the calorimeter water increases by 1.56°C. If the heat capacity of the calorimeter and its contents is 10.0 kJ/°C. Calculate the enthalpy of combustion of fructose at 298 K. (in kJ mol-1)
MEDIUM
JEE Main/Advance
IMPORTANT
The enthalpy of dissociation of PH3 is 954 kJ/mol and that of P2H4 is 1.485 M J mol-1. What is the bond enthalpy of the P-P bond? (in kJ mol-1)
MEDIUM
JEE Main/Advance
IMPORTANT
Using the bond enthalpy data given below, calculate the enthalpy change for the reaction, (in kJ mol-1)

C2H4g+H2gC2H6g

Data :

Bond C-C C=C C-H H-H
Bond Enthalpy 336.81 kJ/mol 606.68 kJ/mol 410.87 kJ/mol 431.79 kJ/mol
MEDIUM
JEE Main/Advance
IMPORTANT
The enthalpy change for the following process at 25°C and under constant pressure at 1 atm are as follows :

CH4gCg+4Hg fH=396 kcal/mole

C2H6g2Cg+6Hg

fH=676 kcal/mole

Calculate C-C bond energy in C2H6 (in kcal mol-1)

Given : subCs=171.8 kcal/mole

B.E. H-H=104.1 kcal/mole

HARD
JEE Main/Advance
IMPORTANT
Find the enthalpy of S-S bond (in kJ mol-1) from the following data.

(i) C2H5-S-C2H5g      Hf°=+147.2 kJ/mol

(ii) C2H5-S-S-C2H2g    Hf°=+201.9 kJ/mol

(iii) Sg                      Hf°=+222.8 kJ/mol

HARD
JEE Main/Advance
IMPORTANT
Calculate the electron affinity of fluorine atom (in kJ mol-1) using the following data. Make Born-Haber's cycle. All the values are in kJ mol-1 at 25°C, HdissF2=160 kJ mol-1, Hf° NaFs=-571 kJ mol-1.I.E. Nag=494 kJ mol-1Hvap=Nas=101kJ mol-1. Lattice energy of NaFs=-894 kJ mol-1.
HARD
JEE Main/Advance
IMPORTANT
Cesium chloride is formed according to the following equation :

Css+0.5Cl2gCsCls.

The enthalpy of sublimation of Cs, enthalpy of dissociation of chloride, ionization energy of Cs & electron affinity of chlorine are 81.2, 243.0, 375,7 and -348.3 kJ mol-1. The energy change involved in the formation of CsCl is -388.6 kJ mol-1. Calculate the lattice energy of CsCl. (in kJ mol-1) enolved.

HARD
JEE Main/Advance
IMPORTANT
The enthalpy of formation of ethane, ethylene and benzene from the gaseous atom are -2839.2, -2275.2 and -5506 kJ mol-1 respectively. Calculate the modulus of resonance energy of benzene (in kJ mol-1). The bond enthalpy of C-H bond is given as equal to +410.87 kJ/mol.