MEDIUM
JEE Main
IMPORTANT
Earn 100

1.46 g of a biopolymer dissolved in a 100 mL water at 300 K exerted an osmotic pressure of 2.42×10-3bar 

The molar mass of the biopolymer is -×104 g mol-1. (Round off to the Nearest Integer)
[Use: R=0.083 L bar mol-1 K-1

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Important Questions on Some Basic Concepts of Chemistry

MEDIUM
JEE Main
IMPORTANT
An organic compound is subjected to chlorination to get compound A using 5.0 g of chlorine. When 0.5 g of compound A is reacted with AgNO3 [Carius Method], the percentage of chlorine in compound A is when it forms 0.3849 g of AgCl. (Round off to the Nearest Integer)
(Atomic masses of Ag and Cl are 107.87 and 35.5 respectively)
MEDIUM
JEE Main
IMPORTANT
When 10 mL of an aqueous solution of KMnO4 was titrated in acidic medium, equal volume of 0.1M of an aqueous solution of ferrous sulphate was required for complete discharge of colour. The strength of KMnO4 in grams per litre is _______×10-2. (Nearest integer) [Atomic mass of K=39,Mn=55,O=16]
MEDIUM
JEE Main
IMPORTANT
The NaNO3 weighed out to make 50 mL of an aqueous solution containing 70.0 mg Na+ per mL is_ g. (Rounded off to the nearest integer) [Given : Atomic weight in gmol-1-Na : 23; N : 14; O : 16]
EASY
JEE Main
IMPORTANT
The number of significant figures in 50000.020×10-3 is                   
MEDIUM
JEE Main
IMPORTANT
An aqueous KCl solution of density 1.20 g mL-1 has a molality of 3.30 mol kg-1. The molarity of the solution in molL-1 is____.(The Nearest integer)
[Molar mass of KCl=74.5 g]
EASY
JEE Main
IMPORTANT
The number of significant figures in 0.00340 is _________
MEDIUM
JEE Main
IMPORTANT
Consider the complete combustion of butane, the amount of butane utilized to produce 72.0 g of water is ______ ×10-1 g. (in nearest integer)
MEDIUM
JEE Main
IMPORTANT
Consider titration of NaOH solution versus 1.25 M oxalic acid solution. At the end point following burette readings were obtained.
(i) 4.5 mL
(ii) 4.5 mL
(iii) 4.4 mL
(iv) 4.4 mL
(v) 4.4 mL
If the volume of oxalic acid taken was 10.0 mL then the molarity of the NaOH solution is ___M. (Rounded-off to the nearest integer)