Alpha Question Bank for Medical: Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Exercise 1>Q 19

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Earn 100

$2$ gram-molecules of $KOH$ dissolved in water to result $500 mL$ solution. Molarity of solution will be:

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Important Questions on Some Basic Concepts of Chemistry

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Alpha Question Bank for Medical: Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Exercise 1>Q 20

Volume of

0.1 M

solution of

HCl

which contains

0.365 g HCl

is:

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Alpha Question Bank for Medical: Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Exercise 1>Q 21

6.02 \times 10^{20}

molecules of urea are present in

100 mL

solution. The concentration of urea solution is:

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Alpha Question Bank for Medical: Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Exercise 1>Q 22

Calculate the amount of

75 %

pure

NaI

required to prepare

5

litre of

0.5 M

solution.

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Alpha Question Bank for Medical: Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Exercise 1>Q 23

A

300 g

solution of density

1.5 g / ml

is prepared by adding

90 g

of glucose

(C_{6} H_{12} O_{6})

in water. Find molarity of this solution.

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Alpha Question Bank for Medical: Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Exercise 1>Q 24

What volume of water is required to make

0.2 M

solution from

16 mL

of a

0.5 M

solution?

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Alpha Question Bank for Medical: Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Exercise 1>Q 25

1 M HCl

and

2 M HCl

solutions are mixed in volume ratio of

4 : 1 .

What is the final molarity of

HCl

solution?

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Alpha Question Bank for Medical: Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Exercise 1>Q 26

10 mL

of concentrated

H_{2} {SO}_{4} (18 M)

is diluted to one litre. The approximate strength of the diluted to one litre.

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Alpha Question Bank for Medical: Chemistry>Chapter 1 - Some Basic Concepts of Chemistry>Exercise 1>Q 27

What volume of

0.25 M {HNO}_{3}

(nitric acid) solution reacts with

50 mL

of

0.15 M

.

{Na}_{2} {CO}_{3}

(sodium carbonate) solution in the following reaction:

2 {HNO}_{3} (aq) + {Na}_{2} {CO}_{3} (aq) ⟶ 2 {NaNO}_{3} (aq) + H_{2} O (l) + {CO}_{2} (g)