Name: Molecules of Elements and Compounds
Uploaded: 2019-07-19
Duration: 3 min 34 s
Description: Each of us has different names to identify ourselves with, don’t we? In the same way, a molecule has a molecular formula to identify itself. Learn more about...

Question

3 g

of Magnesium combines with

2 g

of Oxygen to produce

5 g

of Magnesium oxide compound. If

6 g

of Magnesium is allowed to react with

20 g

of Oxygen, what mass of Magnesium oxide will be produced in the reaction? Name the law which governs your answer.

Accepted Answer

The balanced chemical equation can be written as: $2 {Mg}_{(s)} + O_{2 (g)} \to 2 {MgO}_{(s)}$

By knowing the mass number of Magnesium $(24)$ and Oxygen $(16)$ :

$48 g$ of Magnesium reacts with $32 g$ of Oxygen to form $80 g$ of Magnesium oxide. $\to (1)$

On dividing equation $(1)$ by $16$ , we get

$3 g$ of Magnesium reacts with $2 g$ of Oxygen to give $5 g$ of Magnesium oxide, i.e in the ratio $3 : 2$

Therefore, $(3 \times 2 : 2 \times 2)$

Of $20 g$ of Oxygen, only $4 g$ reacts with $6 g$ of Magnesium to form $10 g$ of Magnesium oxide. While remaining $16 g$ of Oxygen remains unaffected.

This governs the Law of Definite Proportions.

$3 g$ of Magnesium combines with $2 g$ of Oxygen to produce $5 g$ of Magnesium oxide compound. If $6 g$ of Magnesium is allowed to react with $20 g$ of Oxygen, what mass of Magnesium oxide will be produced in the reaction? Name the law which governs your answer.

Important Questions on Atoms and Molecules

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