Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 4

HARD

JEE Main

IMPORTANT

Earn 100

$5 g$ of $K_{2} {SO}_{4}$ was dissolved in $250 mL$ of solution. How many $mL$ of this solution should be used so that $2.33 g$ of ${BaSO}_{4}$ may be precipitated from ${BaCl}_{2}$ solution?

$K_{2} {SO}_{4} + {BaCl}_{2} ⟶ {BaSO}_{4} + 2 KCl$

Important Questions on Some Basic Concepts, Mole Concept and Stoichiometry

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 5

In a solution, the concentration of calcium chloride is

5 M

and that of

{MgCl}_{2}

is

5 M

. The specific gravity of solution is

1.05

. Calculate the concentration of

{Cl}^{-}

in the solution in terms of molarity.

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 6

Given: Mole fraction of the given sample of

I_{2}

in

C_{6} H_{6}

is

0.2

. The molality of

I_{2}

in

C_{6} H_{6}

is

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 7

125 mL

of

10 % NaOH (w / v)

is added to

125 mL

of

10 %

HCl (w / v)

, the resultant solution becomes

EASY

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 8

The molarity of the solution containing

2.8 %

(m / v)

solution of

KOH

is: (Given atomic mass of

K =

39

)

EASY

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 9

500 mL

of

1 M

solution of glucose is mixed with

500 mL

of

1 M

solution of glucose. The final molarity of the solution will be:

EASY

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 10

The molality of a sulphuric acid solution is

0.2

. Calculate the total weight of the solution having

1000 g

of solvent.

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 11

What volumes should you mix

0.2 M NaCl

and

0.1 M

{CaCl}_{2}

solutions so that in the resulting solution the concentration of positive ion is

40 %

lesser than concentration of negative ion. Assume total volume of solution as

1000 ml

.

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 1 - Some Basic Concepts, Mole Concept and Stoichiometry>DPP 1.5>Q 12

100 mL

of

0.8 M NaOH

is used to neutralise

100 mL

of the solution obtained by passing

2.70 g {SO}_{2} {Cl}_{2}

in water. Select the correct statement: