HARD
JEE Main
IMPORTANT
Earn 100

50 mL of H2O2 was treated with excess of KI in the presence of dilute sulphuric acid. I2 so liberated was titrated with 20 mL of 0.1 N hypo solution. Calculate the strength of H2O2 in grams per litre.

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Important Questions on Volumetric Calculation

HARD
JEE Main
IMPORTANT
Calculate the percentage of available chlorine in a sample of 3.546 g of bleaching powder which was dissolved in 100 mL of water; 25 mL of this solution, on treatment with KI and dilute acid, required 20 mL of 0.125 N sodium thiosulphate solution.
HARD
JEE Main
IMPORTANT

A zinc rod weighing 25.00 g was kept in 100 mL of 1 M CuSO4 solution. After a certain time, molarity of Cu2+ in solution was 0.8 M. What was the molarity of the sulphate ion SO42-? What was the weight of the zinc rod after cleaning?

Give the answer upto three places of decimal.

HARD
JEE Main
IMPORTANT

A zinc rod weighing 25.00 g was kept in 100 mL of 1 M CuSO4 solution. After a certain time, molarity of Cu2+ in solution was 0.8 M.

If the above experiment was done with a copper rod of weight 25 g and 50 mL of 2 M zinc sulphate ZnSO4 solution, what would be the molarity of Zn2+ at the end of the same interval? 

HARD
JEE Main
IMPORTANT
25 mL of a mixed solution of Na2CO3 and NaHCO3 required 12 mL of N20 HCl when titrated using phenolphthalein as an indicator. But 25 mL of the same, when titrated separately with methyl orange required 30 mL of N20 HCl. Calculate the amount of Na2CO3 and NaHCO3 in grams per litre. 
HARD
JEE Main
IMPORTANT
20 mL of a mixed solution of Na2CO3 and NaOH required 17.5 mL of N10 HCl when titrated with phenolphthalein as indicator. But when methyl orange was added, a second endpoint was observed on further addition of 2.5 mL of HCl. Calculate the amount of Na2CO3 and NaOH in the solution. 
HARD
JEE Main
IMPORTANT
0.2 g of chloride of an element was dissolved in water and then treated with excess of silver nitrate solution resulting in the formation of 0.47 g of silver chloride. Find the equivalent weight of the element.
HARD
JEE Main
IMPORTANT

A sample of hydrazine sulphate N2H4SO4  was dissolved in 100 mL of water. 10 mL of this solution was reacted with excess of ferric chloride solution and warmed to complete the reaction. Ferrous ion formed was estimated and it required 20 mL of M/50 potassium permanganate solution. Estimate the amount of hydrazine sulphate in one litre of the solution. Reactions:

4Fe++++N2H4N2+4Fe+++4H+

MnO4-+5Fe+++8H+Mn+++5Fe++++4H2O

HARD
JEE Main
IMPORTANT
5 g of bleaching powder was suspended in water and volume was made up to half a litre. 20 mL of this suspension when acidified with acetic acid and treated with excess of KI solution, liberated I2, which required 20 mL of a N/10 hypo solution for titration. Calculate the percentage of available chlorine in bleaching powder.