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A 10 kg satellite completes one revolution around the earth at a height of 100 km in 108 minutes. The work done by the gravitational force of earth will be -

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Important Questions on Work, Energy and Power

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A particle is moved from (0, 0) t o (a, a) under a force F=(3i^ + 4j^) from two paths. Path 1 is OP and path 2 is OQP. Let W1 and W2 be the work done by this force in these two paths. Then :

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A spring of force constant 800 N m-1 has an extension of 5 cm. The work done in extending it from 5 cm to 15 cm is,
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If a spring extends by x on loading then energy stored by the spring is :- (T is tension in the spring, K = spring const.)
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A body of mass 2 kg falls from a height of 20 m. What is the loss in potential energy?
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In stretching a spring by 2 cm energy stored is given by U, then stretching by 10 cm energy stored will be :-
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If the potential energy of two molecules is given by 
U=Ar12-Br6, then at the equilibrium position, its potential energy is equal to
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A 2 g ball of glass is released from the edge of a hemispherical cup whose radius is 20 cm. How much work is done on the ball by the gravitational force during the ball’s motion to the bottom of the cup ?
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4 J of work is required to stretch a spring through 10 cm beyond its unstretched length. The extra work required to stretch it through additional 10 cm shall be :