A $40 \mathrm{kg}$ slab rests on a frictionless floor. A $10 \mathrm{kg}$ block rests on top of the slab. The coefficient of friction between the block and the slab is $0.40.$ The $10 \mathrm{kg}$ block is acted upon by a horizontal force of $100 N.$ If $g=10 \mathrm{m} {\mathrm{s}}^{-2},$ the resulting acceleration of the slab will be

A block of mass $m,$ is kept on a wedge of mass $M,$ as shown in figure such that mass $m$ remains stationary $w.r.t.$ wedge. The magnitude of force $P$ is

Force acting on a body varies with time as shown below. If initial momentum of the body is $\overrightarrow{p},$ then the time taken by the body to retain its momentum $\overrightarrow{p}$ again is

In the figure shown, horizontal force $F_1$ is applied on a block but the block does not slide. Then as the magnitude of vertical force $F_2$ is increased from zero the block begins to slide; the correct statement is

Arrangement of two block system is as shown. The net force acting on $1 \mathrm{kg}$ and $2 \mathrm{kg}$ blocks are (assuming the surfaces to be frictionless) respectively

A dynamometer $\mathrm{D}$ is attached to two blocks of masses $6 \mathrm{kg}$ and $4 \mathrm{kg}$ as shown in the figure. The reading of the dynamometer is

Figure shows two blocks connected by a light inextensible string as shown in figure. A force of $10 \mathrm{N}$ is applied on the bigger block at $60°$ with horizontal, then the tension in the string connecting the two masses is

What is the acceleration of $3 \mathrm{kg}$ mass when acceleration of $2 \mathrm{kg}$ mass is $2 \mathrm{m} {\mathrm{s}}^2$ as shown?