A $60 \mathrm{\mu F}$ parallel plate capacitor whose plates are separated by $6 \mathrm{mm}$ is charged to $250 \mathrm{V}$, and then the charging source is removed. When a slab of dielectric constant $5$ and thickness $3 \mathrm{mm}$ is placed between the plates, find the change in the potential difference across the capacitor?

Can a metal be used as a medium for dielectric?

Two thin dielectric slabs of dielectric constants K₁ and K₂ (K₁ < K₂) are inserted between the plates of a parallel plate capacitor, as shown in the figure. The variation of electric field 'E' between the plates with distance 'd' as measured from plate P is correctly shown by :-

The electrostatic force between the metal plates of an isolated parallel plate capacitor $C$ having a charge $Q$ and area $A$, is 

Electric field between the plates of a capacitor is 5kV/m, separation between plates is 2 mm and dielectric constant of medium is 2. The surface charge density on plates will be :-

If polarization is $\left(\stackrel{\wedge }{\mathrm{i}}+5\stackrel{\wedge }{\mathrm{j}}+2\stackrel{\wedge }{\mathrm{k}}\right)$ unit and E_x = 10 unit then find magnitude electric field.