HARD
11th ICSE
IMPORTANT
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A body is at rest at x=0. At t=0, it starts moving in the positive X direction with a constant acceleration. At the same instant another body passes through x=0 moving in the positive X direction with a constant speed. The position of the first body is given by x1t after time t and that of the second body by x2t after the same time interval. Which of the following graphs correctly describes x1-x2 as a function of time t?

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Important Questions on Motion in One and Two Dimensions

MEDIUM
11th ICSE
IMPORTANT
A particle is moving such that its position coordinates(x,y) are (2m,3m) at time t=0(6m,7m) at time t=2 s and (13 m, 14 m) at time t=5 s. Average velocity vector vav from t=0 to t=5 s is:
MEDIUM
11th ICSE
IMPORTANT
A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms-1 to 20 ms-1 while passing through a distance 135 m In t second. The value of t is:
MEDIUM
11th ICSE
IMPORTANT
From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between Hu and n is :
MEDIUM
11th ICSE
IMPORTANT
A car moving with a speed of 40 km h-1 is stopped in 2 m distance when brakes are applied. If the speed be increased to 80 km h-1, the stopping distance would be:
MEDIUM
11th ICSE
IMPORTANT
Two balls are thrown from the top of a tower, one straight down with an initial velocity u and the other straight up with the same velocity u. They hit the ground with speeds in the ratio:
MEDIUM
11th ICSE
IMPORTANT
A small block slides down a smooth inclined plane, starting from rest at time t=0. Let sn is the distance travelled by the block in the interval t=n-1 to t=n. Then, the ratio snsn+1 is:
EASY
11th ICSE
IMPORTANT
The distance travelled by a particle starting from rest and moving with an acceleration 43 m s-2 in 3rd second is
MEDIUM
11th ICSE
IMPORTANT
An object, moving with a speed of 6.25 ms-1, is decelerated at a rate given bydvdt=-2.5v, where v is the instantaneous speed. The time taken by the object, to come to rest, would be: