A body of mass $10 kg$ is moving with an initial speed of $20 m s^{- 1}$ . The body stops after $5 s$ due to friction between body and the floor. The value of the coefficient of friction is: (Take acceleration due to gravity $g = 10 m s^{- 2}$ )

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Important Questions on Laws of Motion

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Laws of Motion>JEE Main - 1 February 2023 Shift 1>Q 116

A block of mass

5 kg

is placed at rest on a table of rough surface. Now, if a force of

30 N

is applied in the direction parallel to surface of the table, the block slides through a distance of

50 m

in an interval of time

10 s

. Coefficient of kinetic friction is (given,

g = 10 m s^{- 2}

):

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 3 - Laws of Motion>JEE Main - 1 February 2023 Shift 2>Q 117

As shown in the figure a block of mass $10 kg$ lying on a horizontal surface is pulled by a force F acting at an angle $30 °$ , with horizontal. For $μ_{s} = 0.25$ , the block will just start to move for the value of $F$ : [Given g $= 10 m \cdot s^{- 2}$ ]