A body of mass $M$ collides against a wall with velocity $v$ and retraces its path with the same speed. The change in momentum is (take the initial direction of velocity as positive), 

The given figure shows a plot of the time-dependent force $F_x$ acting on a particle in motion along the $X$ axis. What is the total impulse delivered by this force to the particle from time $t=0$ to $t=2$ second?

A ball of mass $3 \mathrm{kg}$ moving with a speed of $100 \mathrm{m} {\mathrm{s}}^{-1},$ strikes a wall at an angle $60°$ (as shown in the figure). The ball rebounds at the same speed and remains in contact with the ball for $0.2 \mathrm{s},$ the force exerted by the ball on the wall is:

In the figure given the position-time graph of a particle of mass $0.1 \mathrm{kg}$ is shown. The impulse at $t=2 s$ is:

A particle of mass $m$ initially at rest, is acted upon by a variable force $F$ for a brief interval of time $T.$ It attains a velocity $u$ after the force stops acting. $F$ is shown in the graph as a function of time. The curve is a semicircle, find $u.$

A mass of $100 \mathrm{g}$ strikes the wall with speed $5 \mathrm{m} {\mathrm{s}}^{-1}$ at an angle as shown in the figure, and it rebounds with the same speed. If the contact time is $2\times {10}^{-3} \mathrm{s},$ what is the force applied on the mass by the wall: